听起来像是Callbackproxy 的工作,每次调用函数参数时都会对其进行评估。我添加了一个简单的例子,我修改了官方的 DEAP n-queen example
这样突变率设置为2/N_GENS(为了说明这一点,任意选择)。
请注意,Callbackproxy 接收 lambda,因此您必须将突变率参数作为函数传递(使用完全成熟的函数或仅使用 lambda)。无论如何,结果是每次评估 indpb 参数时都会调用这个 lambda,如果 lambda 包含对全局变量生成计数器的引用,你就会得到你想要的。
# This file is part of DEAP.
#
# DEAP is free software: you can redistribute it and/or modify
# it under the terms of the GNU Lesser General Public License as
# published by the Free Software Foundation, either version 3 of
# the License, or (at your option) any later version.
#
# DEAP is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with DEAP. If not, see <http://www.gnu.org/licenses/>.
import random
from objproxies import CallbackProxy
import numpy
from deap import algorithms
from deap import base
from deap import creator
from deap import tools
# Problem parameter
NB_QUEENS = 20
N_EVALS = 0
N_GENS = 1
def evalNQueens(individual):
global N_EVALS, N_GENS
"""Evaluation function for the n-queens problem.
The problem is to determine a configuration of n queens
on a nxn chessboard such that no queen can be taken by
one another. In this version, each queens is assigned
to one column, and only one queen can be on each line.
The evaluation function therefore only counts the number
of conflicts along the diagonals.
"""
size = len(individual)
# Count the number of conflicts with other queens.
# The conflicts can only be diagonal, count on each diagonal line
left_diagonal = [0] * (2 * size - 1)
right_diagonal = [0] * (2 * size - 1)
# Sum the number of queens on each diagonal:
for i in range(size):
left_diagonal[i + individual[i]] += 1
right_diagonal[size - 1 - i + individual[i]] += 1
# Count the number of conflicts on each diagonal
sum_ = 0
for i in range(2 * size - 1):
if left_diagonal[i] > 1:
sum_ += left_diagonal[i] - 1
if right_diagonal[i] > 1:
sum_ += right_diagonal[i] - 1
N_EVALS += 1
if N_EVALS % 300 == 0:
N_GENS += 1
return sum_,
creator.create("FitnessMin", base.Fitness, weights=(-1.0,))
creator.create("Individual", list, fitness=creator.FitnessMin)
# Since there is only one queen per line,
# individual are represented by a permutation
toolbox = base.Toolbox()
toolbox.register("permutation", random.sample, range(NB_QUEENS), NB_QUEENS)
# Structure initializers
# An individual is a list that represents the position of each queen.
# Only the line is stored, the column is the index of the number in the list.
toolbox.register("individual", tools.initIterate, creator.Individual, toolbox.permutation)
toolbox.register("population", tools.initRepeat, list, toolbox.individual)
toolbox.register("evaluate", evalNQueens)
toolbox.register("mate", tools.cxPartialyMatched)
toolbox.register("mutate", tools.mutShuffleIndexes, indpb=CallbackProxy(lambda: 2.0 / N_GENS))
toolbox.register("select", tools.selTournament, tournsize=3)
def main(seed=0):
random.seed(seed)
pop = toolbox.population(n=300)
hof = tools.HallOfFame(1)
stats = tools.Statistics(lambda ind: ind.fitness.values)
stats.register("Avg", numpy.mean)
stats.register("Std", numpy.std)
stats.register("Min", numpy.min)
stats.register("Max", numpy.max)
algorithms.eaSimple(pop, toolbox, cxpb=0.5, mutpb=1, ngen=100, stats=stats,
halloffame=hof, verbose=True)
return pop, stats, hof
if __name__ == "__main__":
main()