Python：提取带有特定单词的句子

Question

我有一个包含如下文本的 json 文件：

博士。戈德堡提供一切。停车很好。他很好，很容易 说说

如何提取关键字“停车”的句子？ 我不需要另外两句话。

我试过了：

with open("test_data.json") as f:
    for line in f:
        if "parking" in line:
            print line

它打印所有的文本，而不是那个特定的句子。

我什至尝试过使用正则表达式：

f=open("test_data.json")
for line in f:
    line=line.rstrip()
    if re.search('parking',line):
        print line

即使这显示了相同的结果。

Answer 1

你可以使用nltk.tokenize：

from nltk.tokenize import sent_tokenize
from nltk.tokenize import word_tokenize
f=open("test_data.json").read()
sentences=sent_tokenize(f)
my_sentence=[sent for sent in sentences if 'parking' in word_tokenize(sent)] #this gave you the all sentences that your special word is in it ! 

作为一种完整的方式，您可以使用函数：

>>> def sentence_finder(text,word):
...    sentences=sent_tokenize(text)
...    return [sent for sent in sentences if word in word_tokenize(sent)]

>>> s="dr. goldberg offers everything. parking is good. he's nice and easy to talk"
>>> sentence_finder(s,'parking')
['parking is good.']

Answer 2

解析字符串并查看值怎么样？

import json

def sen_or_none(string):
  return "parking" in string.lower() and string or None

def walk(node):
  if isinstance(node, list):
    for item in node:
      v = walk(item)
      if v:
        return v
  elif isinstance(node, dict):
    for key, item in node.items():
      v = walk(item)
      if v:
        return v
  elif isinstance(node, basestring):
    for item in node.split("."):
      v = sen_or_none(item)
      if v:
        return v
  return None

with open('data.json') as data_file:    
  print walk(json.load(data_file))

Answer 3

可以使用标准库re模块：

import re
line = "dr. goldberg offers everything.parking is good.he's nice and easy to talk"
res = re.search("\.?([^\.]*parking[^\.]*)", line)
if res is not None:
    print res.group(1)

它将打印parking is good。

想法很简单 - 你从可选的点字符 . 开始搜索句子，而不是使用所有非点、parking 单词和其余非点。

问号处理句子在行首的情况。