jq 展平深度嵌套的 json 文档答案

【问题标题】：jq flatten a deeply nested json documentjq 展平深度嵌套的 json 文档
【发布时间】：2022-01-13 05:54:05
【问题描述】：

考虑以下深度嵌套的json对象

[
    {
        "level1key": "level1value",
        "children": [
            {
                "level2key": "level2value1",
                "children": [
                    {
                        "level3key1": "ignored",
                        "level3key2": "ignored",
                        "level3key3": [
                            {
                                "level4key": "ignored"
                            }
                        ]
                    },
                    {
                        "level3key1": "level3value1",
                        "level3key2": "level3value22",
                        "level3key3": [
                            {
                                "level4key": "level4value1"
                            }
                        ]
                    },
                    {
                        "level3key1": "level3value2",
                        "level3key2": "level3value22",
                        "level3key3": [
                            {
                                "level4key": "level4value2"
                            }
                        ]
                    }
                ]
            },
            {
                "level2key": "level2value2",
                "children": [
                    {
                        "level3key1": "ignored",
                        "level3key2": "ignored",
                        "level3key3": [
                            {
                                "level4key": "ignored"
                            }
                        ]
                    },
                    {
                        "level3key1": "level3value3",
                        "level3key2": "level3value22",
                        "level3key3": [
                            {
                                "level4key": "level4value3"
                            }
                        ]
                    },
                    {
                        "level3key1": "level3value4",
                        "level3key2": "level3value22",
                        "level3key3": [
                            {
                                "level4key": "level4value4"
                            }
                        ]
                    }
                ]
            }
        ]
    }
]

我需要通过.[0].children[].children[].level3key2 的“level3value22”进行过滤，并将这个深度嵌套的 json 对象展平为一个数组。预期结果如下。 jq句子应该怎么写？

[
    {
        "v1": "level1value",
        "v2": "level2value1",
        "v3": "level3value1",
        "v4": "level4value1"
    },
    {
        "v1": "level1value",
        "v2": "level2value1",
        "v3": "level3value2",
        "v4": "level4value2"
    },
    {
        "v1": "level1value",
        "v2": "level2value2",
        "v3": "level3value3",
        "v4": "level4value3"
    },
    {
        "v1": "level1value",
        "v2": "level2value2",
        "v3": "level3value4",
        "v4": "level4value4"
    }
]

提前致谢！

【问题讨论】：

标签： json jq flatten

【解决方案1】：

我不确定我是否正确理解了您想要实现的目标，但这至少适用于您的示例数据：

[
  .[0] | [.level1key] + (
    .children[] | [.level2key] + (
      .children[] | select(.level3key2 == "level3value22") | [.level3key1] + (
        .level3key3[] | [.level4key]
      )
    )
  )
  | with_entries(.key |= "v\(. + 1)")
]

[
  {
    "v1": "level1value",
    "v2": "level2value1",
    "v3": "level3value1",
    "v4": "level4value1"
  },
  {
    "v1": "level1value",
    "v2": "level2value1",
    "v3": "level3value2",
    "v4": "level4value2"
  },
  {
    "v1": "level1value",
    "v2": "level2value2",
    "v3": "level3value3",
    "v4": "level4value3"
  },
  {
    "v1": "level1value",
    "v2": "level2value2",
    "v3": "level3value4",
    "v4": "level4value4"
  }
]

Demo

【讨论】：

太棒了！这正是我正在寻找的。span>