将带有 if 条件的 for 循环从单行拆分为多行

Question

我真的对这部分代码感到困惑：

newip = []
c = Counter()
for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]):
   for entry in group:
      c.update(re.findall(r'[0-9]+(?:\.[0-9]+){3}', entry))
   newip.extend(ip for ip, cnt in c.items() if cnt > 10)

如何将这两行分成多行，同时执行相同的任务？

for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]):
...
   newip.extend(ip for ip, cnt in c.items() if cnt > 10)

日志文件：

12/30-04:09:41.070967 [**] [1:10000001:1] snort alert [1:0000001] [**] [classification ID: 0] [Priority ID: 0] {ICMP} 192.168.232.2:41676 -> 192.168.248.2:21
12/30-04:09:41.070967 [**] [1:10000001:1] snort alert [1:0000001] [**] [classification ID: 0] [Priority ID: 0] {ICMP} 192.168.232.2:41673 -> 192.168.248.2:21

现在，我有两个问题：

1. 请解释这两行的具体作用。
2. 如何在执行相同任务的同时将它们分成多行？

感谢和问候。

Answer 1

线

newip.extend(ip for ip, cnt in c.items() if cnt > 10)

会

for ip, cnt in c.items() 
    if cnt > 10:
       #newip.extend( [ip] ) # with [ ]
       newip.append( ip ) # without [ ]

---

线

for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]):

确实（但可能groupby 创建元组列表(key, group) 并且我使用字典）

groups = groupby(logfile, key=lambda e: e.split('.',1)[0])

for key, group in groups.items():

这是我猜的

groups = dict()

for element in logfile:
    key = element.split('.',1)[0]
    if key not in groups:
       groups[key] = []
    groups[key].append(element)

for key, group in groups.items():