如何指定表示特定函数的 arg 类型的类型？

Question

我有一个接受两个参数的函数（下面称为 runLater）：

1. 任意函数
2. 的参数数组 任意函数

像这样：

function runLater(aFunction, aFunctionsParams) {
    // store for later use
}

如何键入 runLater 函数，这样当我将函数作为第一个参数传入时，第二个参数将被限制为该函数的参数类型？

function logNameAndAge(name: string, age: number) {...}

runLater(logNameAndAge, ['hoff', 42]) // ok, the parameter types match up
runLater(logNameAndAge, [false, 'oops']) // no ok, someFunction has [string, number] as paramters

Answer 1

Parameters<T> utility type 轻松搞定！

type func = (...args: any) => any

function runLater<T extends func>(aFunction: T, aFunctionsParams: Parameters<T>) {
    // store for later use
}

function logNameAndAge(name: string, age: number) {}

// ok:
runLater(logNameAndAge, ['hoff', 42])

// errors:
//   Type 'boolean' is not assignable to type 'string'.(2322)
//   Type 'string' is not assignable to type 'number'.(2322)
runLater(logNameAndAge, [false, 'oops'])