Python - 如何提取包含引文标记的句子？

Question

text = "Trondheim is a small city with a university and 140000 inhabitants. Its central bus systems has 42 bus lines, serving 590 stations, with 1900 (departures per) day in average. T h a t gives approximately 60000 scheduled bus station passings per day, which is somehow represented in the route data base. The starting point is to automate the function (Garry Weber, 2005) of a route information agent."
print re.findall(r"([^.]*?\(.+ [0-9]+\)[^.]*\.)",text)

我正在使用上面的代码来提取带有引用的句子。如您所见，最后一句包含引用（Garry Weber，2005）。

但我得到了这个结果：

[' Its central bus systems has 42 bus lines, serving 590 stations, with 1900 (departures per) day in average. T h a t gives approximately 60000 scheduled bus station passings per day, which is somehow represented in the route data base. The starting point is to automate the function (Garry Weber, 2005) of a route information agent.']

结果应该是只包含引用的句子，像这样：
起点是自动化路由信息代理的功能（Garry Weber，2005）。

我猜问题是由括号内的文本引起的，正如您在它包含的第二行（出发）中看到的那样，我的代码有什么解决方案吗？

Answer 1

我的尝试。 Live demo.

\b[^.]+\([^()]+\b(\d{2}|\d{4})\s*\)[^.]*\.

它准确地捕捉了句子，并且比你的年份更具体。