在 Python 中绘制烛台

Question

我想绘制一个有前途的公司的烛台图。我的代码如下：

import numpy as np
import pandas as pd
from pandas_datareader import data as pdr
import fix_yahoo_finance as yf
yf.pdr_override()

#My python 3.6 seem in trouble using pandas_datareader directly,so I install a makeup

gree=pdr.get_data_yahoo('000651.SZ', start='2000-01-01',end='2018-04-30')
gree.info()
gree['Close'].plot(grid=True,figsize=(8,5))
gree['42d']=pd.rolling(gree['Close'],window=42).mean()
gree['42d']=np.round(pd.rolling(gree['Close'],window=42).mean(),2)
gree['252d']=np.round(pd.rolling_mean(gree['Close'],window=252),2)
gree[['Close','42d','252d']].tail()

我遇到了一个问题： AttributeError：模块 'pandas' 没有属性 'rolling'。 虽然我已经阅读了几乎所有可用的答案，但我不知道如何解决它。你可以帮我个忙吗？ :D

Answer 1

我认为需要Series.rolling，查看docs：

所以改变：

gree['42d']=pd.rolling(gree['Close'],window=42).mean()
gree['42d']=np.round(pd.rolling(gree['Close'],window=42).mean(),2)
gree['252d']=np.round(pd.rolling_mean(gree['Close'],window=252),2)

到：

gree['42d'] = gree['Close'].rolling(window=42).mean().round(2)
gree['252d'] = gree['Close'].rolling(window=252).mean().round(2)

或者如果使用下面的熊猫0.18.0：

gree['42d'] = pd.rolling_mean(gree['Close'],window=42)