固定错误实例对象不可调用

Question

我需要使用基于 APIView 类来编辑用户详细信息（如 first_name 、 last_name ）的代码。下面给出了 serializers.py 和 views.py ，但它没有根据用户详细信息进行更改。我正在传递令牌以进行用户身份验证。任何帮助将不胜感激。

Serializers.py

class UserEditSerializer(serializers.Serializer):
    email = serializers.EmailField(required=True)
    first_name = serializers.CharField(required=True)
    last_name = serializers.CharField(required=True)

    def update(self, validated_data, instance):

        instance.first_name = validated_data.get('first_name')
        instance.email = validated_data.get('email')
        instance.last_name = validated_data.get('last_name')
        instance.save()
        return instance

Views.py

class UserEditProfile(APIView):
    authentication_classes = (authentication.TokenAuthentication,)
    permission_classes = (permissions.IsAuthenticated,)

    def get_object(self):
        return self.request.user

    def post(self, request):
        self.object = self.get_object()
        serializer = UserEditSerializer(data=request.data)
        if serializer.is_valid():
            self.object.save()
            return Response(serializer.data, status=status.HTTP_200_OK)
        else:
            return Response(serializer.errors,status=status.HTTP_400_BAD_REQUEST)

Answer 1

此视图将起作用。谢谢莉诺维亚

class UserEditProfile(APIView):
    authentication_classes = (authentication.TokenAuthentication,)
    permission_classes = (permissions.IsAuthenticated,)

    def post(self, request):
        obj = User.objects.get(id=request.user.id)
        serializer = UserEditSerializer(obj, data=request.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data, status=status.HTTP_200_OK)
        else:
            return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

Answer 2

如果您不提供序列化程序，它如何知道它必须更新用户？

    serializer = UserEditSerializer(data=request.data)

应该是：

    serializer = UserEditSerializer(self.object, data=request.data)

编辑： 另外，去掉return instance之后的()