Python 请求超时值错误答案

【问题标题】：Python Requests Timeout Value errorPython 请求超时值错误
【发布时间】：2015-03-20 20:09:14
【问题描述】：

晚上好，

我的 https 请求无法通过。我必须使用 SSLv3，所以我指定协议：

import requests
from requests.adapters import HTTPAdapter
from urllib3.poolmanager import PoolManager
import ssl

class MyAdapter(HTTPAdapter):
     def init_poolmanager(self, connections, maxsize, block=False):
        self.poolmanager = PoolManager(num_pools=connections,
                                        maxsize=maxsize,
                                        block=block,
                                        ssl_version=ssl.PROTOCOL_SSLv3)

username = 'username'
password = 'password'
email = 'email@example.com'
url = 'https://api.example.com/'
headers = {'Accept': 'application/json', 'content-type': 'application/json'}
params = {'emailaddress': email}
auth = (username, password)

s = requests.Session()
s.mount(url, MyAdapter())
r = s.get(url+'customer.svc/search', params=params, auth=auth, headers=headers)

当我运行我的 get 请求时，我收到以下错误：

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/requests/sessions.py", line 473, in get
    return self.request('GET', url, **kwargs)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/requests/sessions.py", line 461, in request
    resp = self.send(prep, **send_kwargs)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/requests/sessions.py", line 573, in send
    r = adapter.send(request, **kwargs)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/requests/adapters.py", line 370, in send
    timeout=timeout
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/urllib3/connectionpool.py", line 517, in urlopen
    timeout_obj = self._get_timeout(timeout)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/urllib3/connectionpool.py", line 283, in _get_timeout
    return Timeout.from_float(timeout)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/urllib3/util/timeout.py", line 152, in from_float
    return Timeout(read=timeout, connect=timeout)
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/urllib3/util/timeout.py", line 95, in __init__
    self._connect = self._validate_timeout(connect, 'connect')
  File "/home/ubuntu/workspace/app/venv/lib/python2.7/site-packages/urllib3/util/timeout.py", line 125, in _validate_timeout
    "int or float." % (name, value))
ValueError: Timeout value connect was Timeout(connect=None, read=None, total=None), but it must be an int or float.

有什么想法吗？我想不通。

附加上下文：我在 Amazon EC2 Ubuntu 实例上，运行请求 2.5.1 和 python 2.7.6

【问题讨论】：

我已经使用 Python 2 和 Python 3 运行了该确切的代码，它对我来说运行完美。看起来我们需要完整的回溯，如果可能的话，还需要所有相关代码
更新了原帖。
什么版本的请求和urllib3？（为了避免不兼容，使用供应商的 urllib3 可能更明智，requests.packages.urllib3 或类似的东西）。

标签： python amazon-ec2 python-requests urllib3

【解决方案1】：

看起来，当您引入外部 urllib3 分发时，请求并不总是很好。我最终做的是调用 requests internal urllib3。

from requests.packages.urllib3.poolmanager import PoolManager

代替：

from urllib3.poolmanager import PoolManager

自从我开始这样做以来没有任何问题。

【讨论】：