python web请求超时错误（requests.exceptions.ConnectTimeout：HTTPSConnectionPool）

Question

我已经编写了一个 python 代码从文件中获取子域并执行 Web 请求我正在使用 get 方法我将超时设置为 5 秒，当请求时间少于 5 秒但当请求时间超过5秒它显示我一个错误。错误说 requests.exceptions.ConnectTimeout: HTTPSConnectionPool(..,..)，我知道与 异常处理 有关，但我不知道它是什么. 下面的代码sn-p：

import requests
import time 

subdomain = []
with open("test.txt","r") as test:
    lines = test.readlines()
count = 0 
for i in lines:
    count = count +1
    subdomain.append(i)

for urls in subdomain:
    
    make_request = requests.get(urls,timeout=5)
    print(make_request.status_code)

Answer 1

我已经删除了您代码中一些不必要的部分，并按照您的要求添加了异常。这是一个可行的解决方案：

import requests
import time 

subdomain = []
with open("test.txt","r") as test:
    subdomain = test.readlines()
count = len(subdomain)

for urls in subdomain:
    try:
        make_request = requests.get(urls,timeout=5)
    except requests.exceptions.ConnectTimeout:
        print("timeout", urls)
        continue
    print(make_request.status_code)

您甚至可以摆脱第二个for loop，因为您的阅读器已经是一个循环：

import requests
import time 

subdomain = []
count = 0
with open("test.txt","r") as test:
    for count, urls in enumerate(test):
        try:
            make_request = requests.get(urls,timeout=5)
        except requests.exceptions.ConnectTimeout:
            print("timeout", urls)
            continue
        print(make_request.status_code)

Answer 2

您可以在请求调用周围添加try/except，处理好的异常

with open("test.txt", "r") as test:
    subdomain = test.read().splitlines()
    count = len(subdomain)

for urls in subdomain:
    try:
        make_request = requests.get(urls, timeout=5)
        print(make_request.status_code)
    except requests.exceptions.ConnectTimeout:
        print("Request to", urls, "timed out")

我也不建议f.readlines()，因为它将换行符保留在每个字符的末尾，而是完整读取然后拆分每一行