完成任务：骰子概率[关闭]

Question

我正在做一项课堂作业。我重新编辑了我的帖子以显示我想要的结果。到目前为止，我被困在频率部分。我想达到这些结果： Results

谢谢！

随机导入

num = int(input("How many times would you like to roll the dice? "))
sides = int(input("How many sides does the dice have? "))

def throwDice(num=1, sides=6):
    return [random.randint(1,sides) for i in range(num)]


#-- main ----------------------------------------------------------------------   

numberOfTrials = int(input('How many trials? Enter:'))



# perform simulation, record and print frequencies
frequency= 13*[0]  # same as [0,0,0,0,0,0,0,0,0,0,0,0,0]

for i in range(numberOfTrials):
   t = throwDice()
   frequency[t[0]+t[0]] += 1;

# end for
print()
print("Frequencies:")
print(frequency)


# calculate relative frequencies, probabilities and errors
relativeFrequency = [0, 0]
probability = [0,0]
error = [0,0]
for i in range(2, len(frequency)):
   relativeFrequency.append(frequency[i]/numberOfTrials)
   probability.append(min(i-1,13-i)/36)
   error.append(abs(probability[i]-relativeFrequency[i]))
# end for


#print(relativeFrequency)
#print(probability)
#print(error)
print()


# print results
f1 = "{0:<10}{1:<22}{2:<22}{3:<22}"
f2 = 71*"-"
f3 = "{0:>3}       {1:<22.15f}{2:<22.15f}{3:<.15f}"
print(f1.format("Sum","Relative Frequency","Probability","Error"))
print(f2)
for i in range(2, len(frequency)):
   print(f3.format(i, relativeFrequency[i], probability[i], error[i]))
#end for
print()

Answer 1

t 是一个 int，所以 t[0] 没有有效意义。

Answer 2

没错。看看你的日常：

def throwDice(rolls=1, dice_sides=6):
    results = 0
    throwDice = 0
    for i in range(0, rolls):
            results = random.randint(1, dice_sides)
    return throwDice

...

   t = throwDice()
   frequency[t[0]+t[1]] += 1;

您制作了给定数量的卷，将最后一个保留在 results 中。然后您忽略该值并返回您最初分配给局部变量throwDice 的0（顺便说一句，它会在本地禁用您的函数定义）。然后将 0 返回给调用程序。

你不能取整数的第一个和第二个元素。

您是如何在不知道您的功能功能失调的情况下积累这么多代码的？在继续之前尝试测试小黑人。事实上，试着测试一下：几分钟的打印语句就可以指出问题所在。请参阅这个可爱的 debug 博客寻求帮助。