如何检查循环中的两个连续输入是否相同（PYTHON）？

Question

我目前正在尝试制作一个程序，它首先询问用户可数整数的数量。然后程序继续向用户单独询问每个可数整数，最后，程序打印计算出的总整数的总和。 这是我的程序的代码：

amount_of_integers = int(input("How many numbers do you want to count together: "))
sum = 0
repeat_counter = 1

while repeat_counter <= amount_of_integers:
    countable_integer = int(input(f"Enter the value of the number {repeat_counter}: "))
    sum += countable_integer
    repeat_counter += 1

print()
print("The sum of counted numbers is", sum)

这就是它目前的工作方式：

How many numbers do you want to count together: 5
Enter the value of the number 1: 1
Enter the value of the number 2: 2
Enter the value of the number 3: 3
Enter the value of the number 4: 4
Enter the value of the number 5: 5

The value of the counted numbers is: 15

现在，棘手的部分来了：如果两个 CONSECTUTIVE 输入都为零 (0)，则程序应该结束。如何创建一个变量来检查程序中每个 CONSECTUTIVE 输入的值是否不为零？我需要创建另一个循环还是什么？

这就是我希望程序工作的方式：

How many numbers do you want to count together: 5
Enter the value of the number 1: 1
Enter the value of the number 2: 0
Enter the value of the number 3: 0

Two consectutive zero's detected. The program ends.

提前致谢！

Answer 1

好吧，让我们先将问题分解为它的组成部分，您有两个要求。

1. 总和
2. 如果连续给出两个零，则退出

你已经完成了一个，对于两个考虑有一个 if 来确定给定值是否是非零值，如果它是零值检查它不等于最后一个值。

你可以修改你的代码如下

amount_of_integers = int(input("How many numbers do you want to count together: "))
sum = 0
repeat_counter = 1
# last integer variable
last_integer = None

while repeat_counter <= amount_of_integers:
    countable_integer = int(input(f"Enter the value of the number {repeat_counter}: "))
    # if statement to validate that if the last_integer and countable_integer
    # are equal and countable_integer is zero then break the loop
    if countable_integer == last_integer and countable_integer == 0:
        break
    else:
        last_integer = countable_integer
    sum += countable_integer
    repeat_counter += 1
    
print()
print("The sum of counted numbers is", sum)