【问题标题】:Convert dates to text in R在 R 中将日期转换为文本
【发布时间】:2019-02-12 16:58:07
【问题描述】:
我有以下日期数据集 (YYYY-MM-DD):
> dates
[1] "20180412" "20180424" "20180506" "20180518" "20180530" "20180611" "20180623" "20180705" "20180717" "20180729"
我想将它们转换为:
DD-MMM-YYYY 但月份是文本。例如20180412 应该变成12Apr2018
关于如何进行的任何建议?
M
【问题讨论】:
标签:
r
list
date
type-conversion
【解决方案1】:
您需要首先将文本字符串解析为Date对象,然后格式化这些Date对象以根据您的喜好获得不同的文本输出:
R> library(anytime) ## one easy way to parse dates and times
R> dates <- anydate(c("20180412", "20180424", "20180506", "20180518", "20180530",
+ "20180611", "20180623", "20180705", "20180717", "20180729"))
R> dates
[1] "2018-04-12" "2018-04-24" "2018-05-06" "2018-05-18" "2018-05-30"
[6] "2018-06-11" "2018-06-23" "2018-07-05" "2018-07-17" "2018-07-29"
R>
R> txtdates <- format(dates, "%d%b%Y")
R> txtdates
[1] "12Apr2018" "24Apr2018" "06May2018" "18May2018" "30May2018"
[6] "11Jun2018" "23Jun2018" "05Jul2018" "17Jul2018" "29Jul2018"
R>
【解决方案2】:
您可以使用as.Date() 和format() 函数:
dts <- c("20180412", "20180424", "20180506", "20180518", "20180530",
"20180611", "20180623")
format(as.Date(dts, format = "%Y%m%d"), "%d%b%Y")
更多信息here
【解决方案3】:
你可以试试这样的:
# print today's date
today <- Sys.Date()
format(today, format="%B %d %Y") "June 20 2007"
where 以下符号可以与 format() 函数一起使用来打印日期1
【解决方案4】:
只需使用as.POSIXct 和as.format:
dates <- c("20180412", "20180424", "20180506")
format(as.POSIXct(dates, format="%Y%m%d"),format="%d%b%y")
输出:
[1] "12Apr18" "24Apr18" "06May18"