MongoDB和Mongoose - 来自两个不同集合查询的ID不匹配

Question

我正在构建一个应用程序，人们可以在其中制作聚餐并邀请其他用户参加他们的聚餐。我有一个看似简单的问题，但我无法让它工作：

我想创建一个邀请路由来检查 potluck.attendees 以查看他们之前是否被邀请过（并根据他们是 0-pending、1-attending 还是 发送不同的错误如果他们之前被邀请过并且他们的状态为 2 denied，则重新邀请他们），如果没有，则将被邀请者放入 potluck.attendees 对象数组中，将 potluck 的 _id 放入被邀请者的 user.potlucks 对象数组中。

以下是这两个模型的超级修剪版本：

简化的家常便饭模型

const PotluckSchema = new Schema({
  attendees: [
    {
      attendeeId: {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'User'
      },
      status: Number,
      enums: [
        0, //'pending',
        1, //'attending',
        2 //'declined'
      ]
    }
  ]
});

简化的用户模型

const UserSchema = new Schema({
  potlucks: [
    {
      potluck: {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'Potluck'
      }
    }
  ]
});

到目前为止，我在这条路线上拥有的是：

router.put('/attendees/invite/:potluckId/:inviteeId', async (req, res) => {
  try {
    const currPotluck = await db.Potluck.findOne({
      _id: req.params.potluckId,
      createdBy: req.user._id
    });
    // Makes sure potluck belongs to user before allowing to invite
    if (!currPotluck)
      return res.status(401).json({
        msg: 'You are not authorized to invite people to this potluck.'
      });
    const invitee = await db.User.findOne({ _id: req.params.inviteeId });

    console.log(currPotluck);
    console.log(invitee);

    for (let i = 0; i < currPotluck.attendees.length; i++) {
      //  Checks if invitee already exists in potluck.attendees
      //  and if their status is 0 or 1 (pending or attending)
      //  It will stop function
      if (
        currPotluck.attendees[i].attendeeId == invitee._id &&
        currPotluck.attendees[i].status == 0 ||
        currPotluck.attendees[i].attendeeId == invitee._id &&
        currPotluck.attendees[i].status == 1
      ) {
        return res.status(401).send({
          error: 'This member has already been invited to your potluck'
        });
      } else if (
        currPotluck.attendees[i].attendeeId == invitee._id &&
        currPotluck.attendees[i].status == 2
      ) {
        //  if their status is 2 (declined)
        //  it will edit their existing object in the attendees array to pending
        //  and re-insert potluck in invitee's user.potlucks model
        await db.Potluck.findOneAndUpdate(
          { _id: currPotluck._id },
          { $set: { 'attendees.$[el].status': 0 } },
          { arrayFilters: [{ 'el.attendeeId': invitee._id }] }
        );
        await db.User.findOneAndUpdate(
          { _id: invitee._id },
          { $push: { potlucks: { potluck: currPotluck._id } } }
        );
        res.send(`This user has been re-invited to your potluck!`);
      }
    }
    // If they don't exist already in potluck.attendees, create new object
    // in potlucks.attendees and user.potlucks for invitee
    await db.Potluck.findOneAndUpdate(
      { _id: currPotluck._id },
      { $push: { attendees: { attendeeId: invitee._id, status: 0 } } }
    );
    await db.User.findOneAndUpdate(
      { _id: invitee._id },
      { $push: { potlucks: { potluck: currPotluck._id } } }
    );
    res.send(`This user has been invited to your potluck!`);
  } catch (err) {
    console.error(err.message);
    res.status(500).send('Server Error');
  }
});

现在开始：

如果我在邮递员中运行此代码，它将运行在 for 循环之后出现的两个“findOneAndUpdate”，无论是否匹配。在尝试调试时，我 console.logged invitee._id 和 currPotluck.attendees[i].attendeeId （用于我知道被邀请者已经存在于数组中的测试）并且它们都以相同的 id 出现。

但如果我尝试console.log (currPootluck.attendees[i].attendeeId == invitee._id)，它每次都会出现false。我为两者做了一个“类型”，它们作为对象出现，并且它们在 console.logs 中看起来都是相同的类型 - 可能是字符串？

我知道解决方案必须非常简单，但我无法弄清楚，任何帮助将不胜感激！

Answer 1

currPootluck.attendees[i].attendeeId和invitee._id都是ObjectIds，为了检查它们是否相同，必须先将其转换为字符串。

这应该可以完成工作：currPootluck.attendees[i].attendeeId.toString() == invitee._id.toString()