将 std::ofstream 对象作为参数传递给类方法

Question

正如前面的问题已经回答，将std::ofstream 对象作为函数参数传递的方法似乎是传递一个引用：std::ofstream&。

虽然此解决方案可以编译，但生成的输出并不等同于在方法中创建 std::ofstream 对象然后调用 write()。

下面的代码没有给出正确的输出：

在ma​​in.cpp中：

std::ofstream file(path + "output.stubs");
stub->writeRaw(file); //stub is a pointer to an object of class Stub
file.close();

在 Stub.cpp 中：

void Stub::writeRaw(std::ofstream& file) {
    file.write((char*)this, sizeof(*this));
}

正确的输出是通过将 Stub.cpp 更改为：

void Stub::writeRaw(void) {
    std::ofstream file(path + "output.stubs");
    file.write((char*)this, sizeof(*this));
    file.close();
}

或将对象写入 main 中的文件，而不是调用类方法。

任何有关此行为的帮助将不胜感激！

编辑

类 Stub 的一些上下文：

Stub.hpp

#pragma once

#include <iostream>
#include <ios>
#include <fstream>

#include "constants.hpp"
#include "DataTypes.hpp"


class Stub {
private:
    StubHeader header;
    StubIntrinsicCoordinates intrinsic;
    StubPayload payload;

public:
    Stub(void);
    virtual ~Stub(void);

    StubHeader getHeader(void);
    StubIntrinsicCoordinates getIntrinsicCoordinates(void);
    StubPayload getPayload(void);

    void setHeader(StubHeader stub_header);
    void setIntrinsicCoordinates(StubIntrinsicCoordinates stub_intrinsic);
    void setPayload(StubPayload stub_payload);

    void print(void);
    void writeRaw(std::ofstream& file);
};

相关数据类型定义如下：

struct StubHeader {
    uint8_t bx;
    uint8_t nonant;
};

struct StubIntrinsicCoordinates {
    uint8_t strip;
    uint8_t column;
    int crossterm;
};

struct StubPayload {
    bool valid;
    int r;
    int z;
    int phi;
    int8_t alpha;
    int8_t bend;
    uint8_t layer;
    bool barrel;
    bool module;
};

编辑 2

读取存根的（玩具）代码如下：

std::ifstream r(path + "output.stubs");
Stub s;
r.read((char*)&s, sizeof(s));
s.print();

只有一个存根写入文件，因为这是对功能的测试。 Stub类的打印函数如下：

void Stub::print(void) {
    std::cout << "----- Header -----" << '\n';
    std::cout << "bx: " << std::dec << (int)header.bx << '\n';
    std::cout << "nonant: " << std::dec << (int)header.nonant << '\n';
    std::cout << "----- Intrinsic Coordinates -----" << '\n';
    std::cout << "strip: " << std::dec << (int)intrinsic.strip << '\n';
    std::cout << "column: " << std::dec << (int)intrinsic.column << '\n';
    std::cout << "crossterm: " << std::dec << (int)intrinsic.crossterm << '\n';
    std::cout << "----- Payload -----" << '\n';
    std::cout << "valid: " << std::boolalpha << payload.valid << '\n';
    std::cout << "r: " << std::dec << (int)payload.r << '\n';
    std::cout << "z: " << std::dec << (int)payload.z << '\n';
    std::cout << "phi: " << std::dec << (int)payload.phi << '\n';
    std::cout << "alpha: " << std::dec << (int)payload.alpha << '\n';
    std::cout << "bend: " << std::dec << (int)payload.bend << '\n';
    std::cout << "layer: " << std::dec << (int)payload.layer << '\n';
    std::cout << "barrel: " << std::boolalpha << payload.barrel << '\n';
    std::cout << "module: " << std::boolalpha << payload.module << "\n\n";
}

编辑 3

为了完整和透明，请在下面找到 ma​​in.cpp 的确切代码：

int main(int argc, char const *argv[]) {
    Geometry g;
    g.generateModuleLUTs();
    g.generateCorrectionLUTs();
    std::vector<std::array<Stub*, PAYLOAD_WIDTH> > all_stubs;
    std::vector<Module> modules = g.getData(); 
    for (int i = 0; i < LINK_NUMBER; i++) {
        LinkGenerator link_gen;
        LinkFormatter link_formatter(link_gen.run());
        StubFormatter stub_formatter(link_formatter.run(), i);
        std::array<Stub*, PAYLOAD_WIDTH> stubs = stub_formatter.run(modules);
        CoordinateCorrector coordinate_corrector(stubs);
        all_stubs.push_back(coordinate_corrector.run());
    }
    std::ofstream f(path + "output.stubs");
    all_stubs[0][0]->writeRaw(f);
    all_stubs[0][0]->print();
    std::ifstream r(path + "output.stubs");
    Stub s;
    r.read((char*)&s, sizeof(s));
    s.print();
    return 0;
}

Answer 1

代码中的错误是我在构造std::ifstream 对象以再次读取文件之前没有调用file.close()。这是意外行为的原因。

使用this 将类写入文件似乎是有效的，但重要的是要小心并确切地知道要写入文件的内容。

感谢所有评论并帮助回答这个问题的人！