【发布时间】:2021-05-28 23:45:33
【问题描述】:
在 Z3py 中是否有不同的方法来划分两个 z3.z3.ArithRef 变量?这是我的示例代码:
from z3 import *
X = Int('X')
s = Solver()
def pick(X):
return Or([X==p for p in [0,1]])
var1 = 2.5
var2 = 6.5
total1 = 0
for i in range(5):
total1 = total1 + If(X == 1, var1 * ToReal(X), 0)
total2 = 0
for i in range(5):
total2 = total2 + If(X == 0, var2 + ToReal(X), 0)
s.add(total1/total2 > 0)
r = s.check()
if r == sat:
m = s.model()
print(m)
else:
print("Solver said: %s" % r)
添加约束s.add(total1/total2 > 0) 后的输出给了我一些额外的元素:[X = 2, /0 = [else -> 1]]。这适用于乘法,即s.add(total1*total2 == 0)。
为什么要添加/0 = [else -> 1],如何避免这种情况?
【问题讨论】:
标签: python-3.x z3 z3py