根据 MySQL 中的日期对两个表中的总和进行分组

Question

我有两个不同的表，lead 和 click。我想查询 MySQL 以获取按日期排序的点击和潜在客户产生的佣金总和。

领导：

id|date      |commission
 1|2009-06-01|400
 2|2009-06-01|300
 3|2009-06-03|350

点击：

id|date      |commission
 1|2009-06-01|1
 2|2009-06-03|2
 3|2009-06-03|1

我想创建一个给我的查询（如果可能的话，还可以获取没有生成潜在客户或点击的日期）：

date      |commission click|commission lead|total commission
2009-06-01|               1|            700|             701
2009-06-02|               0|              0|               0
2009-06-02|               3|            350|             353

（日期实际上是真实数据库中的日期时间。）

我想我必须结合：

SELECT count(*) as number_clicks, sum(click.commission) as sum_clicks,
 date(click.time) as click_date from click group by click_date order by click_date

与：

SELECT count(*)as number_leads, sum(lead.commission) as sum_leads,
 date(lead.time) as lead_date from lead group by lead_date order by lead_date

但我不能让他们一起工作。

Answer 1

这不会得到带有零的日期，因为您需要一个日期表或一个存储过程来循环日期。一种方法是从联合查询中进行子选择（未经测试）：

SELECT commission_date, SUM(click_commission), SUM(lead_commission), SUM(total_commission)
FROM (SELECT DATE(click.time) AS commission_date, click.commission AS click_commission,
             0 AS lead_commission, click.commission AS total_commission
      FROM click
      UNION ALL
      SELECT DATE(lead.time) AS commission_date, 0 AS click_commission,
             lead.commission AS lead_commission, lead.commission AS total_commission
      FROM lead) AS foo
GROUP BY commission_date
ORDER BY commission_date