MySQL Min value query group by 第二列没有得到第三列的正确值答案

【问题标题】：MySQL Min value query group by second column not getting the proper value of third columnMySQL Min value query group by 第二列没有得到第三列的正确值
【发布时间】：2013-03-01 00:26:28
【问题描述】：

我的表结构如下

vendor_id account_id 价格代码

27 2 0.058 91

29 2 0.065 91

23 2 0.043 91

30 2 0.085 91

31 3 0.085 91

我必须得到代码应该等于 91 的最低价格，给定范围和按 account_id 分组的价格

我正在使用选择查询作为

从 tbl_input_values 中选择 MIN(price) 作为 min_price、account_id、vendor_id 其中 code='91' and price>=0 and price

我得到的输出为

min_price account_id vendor_id

0.043 2 27

0.085 3 31

但应该是的

min_price account_id vendor_id

0.043 2 23

0.085 3 31

【问题讨论】：

full_code 或 code ?
欣赏它的代码，在查询中误写为full_code

标签： php mysql

【解决方案1】：

试试这个查询 -

SELECT
  t1.*
FROM tbl_input_values t1
JOIN (
  SELECT
    MIN(price) AS min_price,
    account_id
  FROM tbl_input_values
  WHERE code = '91' AND price >= 0 AND price <= 2
  GROUP BY account_id
  ) t2
    ON t1.account_id = t2.account_id AND t1.price = t2.min_price

【讨论】：

【解决方案2】：

您的查询正确选择了每个 account_id 的最低价格，但有必要将此价格与 vendor_id 关联起来。

这是我的版本：

SELECT iv.price AS min_price, iv.account_id, iv.vendor_id
  FROM tbl_input_values AS iv
  INNER JOIN (select min(price) AS min_price, account_id
    FROM tbl_input_values
    WHERE full_code='91' AND price>=0 AND price<=2
    GROUP BY account_id) AS mp
 ON iv.price=mp.min_price AND iv.account_id=mp.account_id;

如果两个供应商的 account_id 最低价格相同，则此查询将返回两者。

在此处查看 SQL 小提琴http://sqlfiddle.com/#!2/96d24/8

【讨论】：

【解决方案3】：

试试这个查询

 SELECT 
      price, 
      account_id, 
      vendor_id 
 from 
      Table1
 where 
      (vendor_id, price) in 
      (select 
            vendor_id, 
            min(price) 
       from 
            Table1 
       WHERE 
            code = '91' AND 
            price >= 0 AND 
            price <= 2
       group by 
            account_id)

没有使用连接的子查询

  SELECT 
        a.price, 
        a.account_id, 
        a.vendor_id 
  from 
        Table1 a,
        (select 
               vendor_id, 
               min(price) as 'price' 
        from 
               Table1 
        where 
               code='91' and 
               price>=0 and 
               price<=2
        group by 
               account_id) b
  WHERE 
        a.vendor_id = b.vendor_id AND 
        a.price = b.price

【讨论】：

【解决方案4】：

试试；

SELECT tData.price, tData.account_id, tData.vendor_id FROM tbl_input_values, (SELECT price, account_id, vendor_id FROM tbl_input_values ORDER BY price ASC) AS tData WHERE tbl_input_values.account_id = tData.account_id GROUP by tbl_input_values.account_id;

【讨论】：