如果单词不在列表applescript中，则显示对话框

Question

我正在编写一个可以为我打开和关闭应用程序的脚本。基本上，我输入一个应用程序名称，然后它会打开应用程序。唯一的事情是，如果未找到该应用程序，它会引发错误并退出。我想让脚本只显示一个对话框，上面写着“找不到应用程序”。

这是我目前所拥有的：

if userInput contains "Activate " then set {TID, text item delimiters} to {text item delimiters, {"Activate "}}
if length of userInput is less than or equal to 1 then say (resultString as string)
if length of userInput is greater than or equal to 2 then set resultString to text item 2 of userInput
set openApp to (resultString as string)
if userInput contains "Activate " then set text item delimiters to TID
if userInput contains "Activate " then tell application (openApp as string) to activate

顺便说一句，这只是我脚本的一个 sn-p，这就是为什么这里有一些未定义的变量。

我试过了：

set appList to do shell script "cd /Applications; ls"
if openApp is not in appList then display dialog "App not found"

嗯，Applescript 语法有时很烦人。

谢谢。

Answer 1

有exists application，但也会弹出一个对话框询问“xyz 在哪里？”。

所以你能做的最好的事情似乎是：

tell application "Finder" to set appExists to (exists file myApp of folder "Applications" of startup disk)

if not appExists then
    display alert "App not found"
end if

你的代码是：

if userInput contains "Activate " then set {TID, text item delimiters} to {text item delimiters, {"Activate "}}
if length of userInput is less than or equal to 1 then say (resultString as string)
if length of userInput is greater than or equal to 2 then set resultString to text item 2 of userInput
set openApp to (resultString as string)

if userInput contains "Activate " then set text item delimiters to TID

tell application "Finder" to set appExists to (exists file (openApp & ".app") of folder "Applications" of startup disk)
if not appExists then
    display alert "App not found"
else
    if userInput contains "Activate " then tell application (openApp as string) to activate
end if

或者在用户按下取消时尝试捕捉错误：

try
    if userInput contains "Activate " then tell application (openApp as string) to activate
on error
    display alert "App not found"
end try