【发布时间】:2020-05-03 20:47:03
【问题描述】:
我正在尝试使用 AJAX 实现 JSF 按钮,如果不满足某些条件,则使用 AJAX 形成该按钮。我试过这个例子:
<h:form id="paymentform" enctype="multipart/form-data" x:data-form-output="form-output-global" x:data-form-type="contact" class="rd-mailform text-left">
<h:commandButton id="buy" class="btn btn-primary" type="submit" value="Put" action="#{dashboard.calculateProcessing}" >
<f:ajax render="@form" execute="@form" x:data-toggle="modal" x:data-target="#demoModal"/> // if #{dashboard.amount} <= 0 call modal dialog
</h:commandButton>
<div class="modal fade" id="demoModal" role="dialog">
.....
</div>
</h:form>
@Named
@SessionScoped
public class Dashboard implements Serializable {
private static final long serialVersionUID = -2363083605115312742L;
private double amount;
public double getAmount() {
return amount;
}
public void setAmount(double amount) {
this.amount = amount;
}
}
如果我这样编辑按钮:
<h:commandButton id="buy" class="btn btn-primary" type="submit" value="Put" action="#{dashboard.calculateProcessing}" x:data-toggle="modal" x:data-target="#demoModal" >
显示对话框并提交表单。
但是如果不满足 Bean 的某些条件,我找不到如何不提交表单的解决方案。您能指导我如何找到解决方案吗?
【问题讨论】:
-
我更新了答案。这是我能想到的。