【发布时间】:2014-10-30 11:28:05
【问题描述】:
我正在尝试比较 2 个位图中矩形的相等性。我正在使用 AForge 库。一个是模板,另一个是表格。我试过这个,但对我来说似乎很粗糙,因为它有太多的迭代,这使得程序非常慢。它可以工作,但问题是程序由于迭代次数过多而挂起。请问有什么我想念的吗?我是在正确的轨道上还是什么?请帮助并原谅我下面的粗略代码。 位图 bitmap = new Bitmap(pictureBox1.Image); 位图bitmap2 = new Bitmap(pictureBox2.Image);
// create an instance of blob counter algorithm
BlobCounter blobCounter = new BlobCounter();
blobCounter.MinWidth = 5;
blobCounter.MinHeight = 5;
blobCounter.FilterBlobs = true;
blobCounter.ObjectsOrder = ObjectsOrder.Size;
blobCounter.ProcessImage(bitmap);
BlobCounter blobCounter2 = new BlobCounter();
blobCounter2.MinWidth = 5;
blobCounter2.MinHeight = 5;
blobCounter2.FilterBlobs = true;
blobCounter2.ObjectsOrder = ObjectsOrder.Size;
blobCounter2.ProcessImage(bitmap2);
Rectangle[] rects = blobCounter.GetObjectsRectangles();
Rectangle[] rects2 = blobCounter2.GetObjectsRectangles();
foreach (Rectangle recs in rects)
foreach (Rectangle recs2 in rects2)
if (rects.Length > 0 )
{
if (rects2.Length > 0)
{
for (int x = 0; x < recs.Width & x < recs.Height; x++)
{
// for (int x2 = 0; x2 < recs2.Width; x2++)
for (int y = 0; y < recs2.Width & y < recs2.Height; y++)
{
// for (int y2 = 0; y2 < recs2.Height; y2++)
if (recs.Equals(recs2))
{
this.Refresh();
//listBox1.Items.Add("TRUE");
Console.WriteLine("TRUE");
}
else
{
//listBox1.Items.Add("FALSE");
Console.WriteLine("FALSE");
}.....
【问题讨论】:
标签: c# bitmap equality rectangles aforge