【发布时间】:2017-02-20 17:37:51
【问题描述】:
如何将此字典列表排序和分组到一个嵌套字典中,我想通过 API 作为 JSON 返回该字典。
源数据(权限列表):
[{
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 1,
'can_update': True,
'end_point_name': 'entity',
'can_delete': True,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleTwo',
'module_id': 2,
'role_id': 1,
'end_point_id': 4,
'can_update': True,
'end_point_name': 'financial-outlay',
'can_delete': True,
},{
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 2,
'can_update': True,
'end_point_name': 'management-type',
'can_delete': True,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleOne',
'module_id': 1,
'role_id': 1,
'end_point_id': 3,
'can_update': True,
'end_point_name': 'ownership-type',
'can_delete': False,
}, {
'can_create': True,
'can_read': True,
'module_name': 'ModuleTwo',
'module_id': 2,
'role_id': 1,
'end_point_id': 5,
'can_update': True,
'end_point_name': 'exposure',
'can_delete': True,
}]
我想将其转换为嵌套的字典对象,以便使用 API 作为 JSON 返回。这是预期的输出:
{
"role_id": 1,
"modules": [{
"module_id": 1,
"module_name": "ModuleOne",
"permissions": [{
"end_point_id": 1,
"end_point_name": "entity",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 2,
"end_point_name": "management-type",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 3,
"end_point_name": "ownership-type",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, ]
}, {
"module_id": 2,
"module_name": "ModuleTwo",
"permissions": [{
"end_point_id": 4,
"end_point_name": "financial-outlay",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, {
"end_point_id": 5,
"end_point_name": "exposure",
"can_create": False,
"can_read": True,
"can_write": True,
"can_delete": True
}, ]
},
]
}
它看起来微不足道,直到我花更多的时间来尝试弯曲我的想法。我尝试了很多选择,但没有一个有效。这是最后一次尝试。
# Get user role
user_roles = get_user_roles() # List of roles e.g. [{'role_id':1, role_name: 'role_one'}, {'role_id':2, role_name: 'role_two'}]
for role in user_roles:
role_id = role['role_id']
role_name = role['role_name']
# Fetch Role Permissions
role_permissions = get_role_permissions(role_id) # List of permissions as seen above
sorted_role_permissions = sorted(role_permissions, key=itemgetter('module_id')) # sort dictionaries in list by 'module_id'
modules_list = []
permissions_list = []
previous_module_id = 0
is_first_loop = True
for role_permission in sorted_role_permissions:
module_id = role_permission['module_id']
module_name = role_permission['module_name']
end_point_id = role_permission['end_point_id']
end_point_name = role_permission['end_point_name']
if is_first_loop:
print(0)
is_first_loop = False
previous_module_id = module_id
print('end_point_name 0 {}'.format(end_point_name))
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)
if len(sorted_role_permissions) == 1:
# If there is only one permission in the role, end the loop
modules_dict = {'module_id': module_id, 'module_name': module_name,
'permissions': permissions_list}
modules_list.append(modules_dict)
break
else:
if module_id == previous_module_id:
# As long as the current module_id and the previous_module_id are the same, add to the same list
print(1)
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)
else:
print(2)
modules_dict = {'module_id': module_id, 'module_name': module_name,
'permissions': permissions_list}
modules_list.append(modules_dict)
permissions_list = []
permissions = {'end_point_id': end_point_id, 'end_point_name': end_point_name,
'can_create': role_permission['can_create'],
'can_read': role_permission['can_read'],
'can_update': role_permission['can_update'],
'can_delete': role_permission['can_delete']
}
permissions_list.append(permissions)
previous_module_id = module_id
if modules_list:
roles.append({'role_id': role_id, 'role_name': role_name, 'modules': modules_list})
【问题讨论】:
-
如果有多个角色,结果应该是什么?如果角色不同,模块可以有相同的id吗?
-
如果有多个角色,那么您将有另一个“字典列表”,顶部节点为“role_id & role_name”。但请注意,要获取权限列表,传递role_id
(get_role_permissions(role_id)这意味着 role_permissions 中不会有多个角色。是的,模块可以分配给多个角色,但请记住,我们传递了role_id,它负责处理上述问题。例如,上面list of permissions中给出的示例数据在所有字典中都有一个role_id
标签: python list python-3.x dictionary