根据数组中 I 时间的每个持续时间播放快速声音答案

【问题标题】：Play swift sound based on each duration of I time in array根据数组中 I 时间的每个持续时间播放快速声音
【发布时间】：2020-12-09 04:05:25
【问题描述】：

我希望我的快速代码调用 playSound 并根据数组 playamount 中每个项目的持续时间播放声音。所以我希望用户第一次播放声音 10 秒，然后从头开始播放声音 20 秒，然后同样的声音 30 秒。所以每次调用时，声音总是从头开始。

import UIKit;  import AVFoundation

class ViewController: UIViewController {
    
  

    var player: AVAudioPlayer?

    func playSound() {
        let url = Bundle.mainBundle().URLForResource("rock", withExtension: "mp3")!

        do {
            player = try AVAudioPlayer(contentsOfURL: url)
            guard let player = player else { return }

            player.prepareToPlay()
            player.play()

        } catch let error as NSError {
            print(error.description)
        }
    }
    var playAmount : [Int] = [10,20,30]

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
    }


}

【问题讨论】：

标签： arrays swift loops audio duration

【解决方案1】：

class ViewController: UIViewController {

    var player: AVAudioPlayer?
    var currentIndex: Int = 0

    func runMusicBox() {
        guard !playAmount.isEmpty else { return }
        currentIndex = 0
        newTimerForIndex(index: 0)
    }
    
    func newTimerForIndex(index: Int) {
        player?.prepareToPlay()
        player?.play()
        Timer.scheduledTimer(withTimeInterval: Double(playAmount[index]), repeats: false) { timer in
            self.player?.stop()
            if self.currentIndex + 1 < self.playAmount.count {
                self.currentIndex += 1
                self.newTimerForIndex(index: self.currentIndex)
            } else {
                self.player?.stop()
            }
        }
    }
    
    func playSound() {
        let url = Bundle.mainBundle().URLForResource("rock", withExtension: "mp3")!

        do {
            player = try AVAudioPlayer(contentsOfURL: url)
            guard let player = player else { return }
            runMusicBox()

        } catch let error as NSError {
            print(error.description)
        }
    }
    var playAmount : [Int] = [10,20,30]

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
    }


}

你好，你能试试这个代码吗？这里我有一个计时器，当一个计时器停止时，我们检查数组中是否还有另一个元素，然后运行一个新的计时器。计时器正在工作，但我没有检查播放器。如果它按预期工作 - 它应该适合你

【讨论】：