模拟 NETWORKDAYS 返回错误的工作日

Question

我在基于this solution 的 sql 上创建了一个类似 NETWORKDAYS 的函数，它可以正确返回工作日，而记录（BEG 和 END）在工作日。

BEG        END         businessd
--------------------------------
01/01/2018 15/01/2018  10       

--(15 days total)-(1st jan)-(4 weekends) = 10 | correct result

但在某些情况下，如果 BEG 或 END 被“存储”在周末，它会计算额外的天数：

BEG        END         businessd
--------------------------------
01/01/2018 28/01/2018  20       

--(28 days total)-(1st jan)-(4 weekends) = 19 | incorrect result

我的代码在BEG 和FIN 之间执行datediff，并减去存储在holydays 表中的周末和圣日

    SELECT e.*, 
            DATEDIFF(DAY, cast(BEG as datetime), cast(FIN as datetime))+1 --sum end date day
              -(SELECT
               (DATEDIFF(WK, cast(BEG as datetime), cast(FIN as datetime)) )
              +(CASE WHEN DATENAME(dw, cast(BEG as datetime)) = 'Sunday' THEN 1 ELSE 0 END)
              +(CASE WHEN DATENAME(dw, cast(FIN as datetime)) = 'Saturday' THEN 1 ELSE 0 END)
            ) * 2
            -(SELECT COUNT(*) FROM holydays nl
             WHERE nl.FECHA BETWEEN cast(BEG as datetime) AND cast(FIN as datetime)
            ) AS businessd,

            convert(nvarchar(6),cast(BEG as datetime),112) as iddate --new id based on fin
    FROM e
    ORDER BY original_ini,BEG

我该如何处理这些情况才能正确计算工作日？

Answer 1

您可以为此目的使用日历表。有了它，这个操作会很简单。

你甚至可以处理银行假期

Check This 和 this (Calendar Table)

select * from calendar where isWorkDay = 1  

会给你工作日，然后你可以像这样简单地加入

select * from t
where exists 
( select 1 from calendar where isWorkDay = 1 and calendar.dt betweenn t.beg and t.end)