python将字符序列拆分为单独的列表[重复]

Question

如果您要在一个序列中包含一串字符/数字 - 比如说 AACBDEFZZBGFAAFFGGCCEEZZ

如何遍历字符串，然后让 AA 和 ZZ 之间的每个字符都出现在列表中？这种情况下的最终结果是：

[CBDEF], [FFGGCCEE] ?

谢谢

Answer 1

你可以使用str.index:

def between_markers(s, starting_marker="AA", ending_marker="ZZ"):
    # keep track of where the previous marker was found
    prev_ind = 0
    ret = []
    while True:
        try:
            # find the starting marker
            start = s.index(starting_marker, prev_ind) + len(starting_marker)
            # find the ending marker
            end = s.index(ending_marker, start)
            prev_ind = end + len(ending_marker)
            # slice and append to return list
            ret.append(s[start:end])
        except ValueError:
            # couldn't find one of the two markers so we're done
            break
    return ret

between_markers("AACBDEFZZBGFAAFFGGCCEEZZ") # ['CBDEF', 'FFGGCCEE']