尝试从函数返回布尔值

Question

我正在尝试编写一个简单的基于文本的游戏。为了做到这一点，我让用户去三个不同的房间完成一项任务并收到一块。为此，我将值设置为False，然后，在房间完成后，我有一个return 语句用于将布尔值更改为True。当所有三个房间函数都返回 True 时，我将其设置为打开一个推进游戏的函数。然而，众所周知，返回不会发生，因此布尔值保持不变。 下面是一个门函数的例子：

def door1(incomp1):
    if incomp1 == False:
        print 'You enter door 1 and find a hideous internet troll.'
        print "The troll says, 'LOOK AT THIS LOSER'"
        options = ["YOU'RE THE LOSER", "I don't care." , "YOUR MOM IS FAT"]
        options2 = [1,2,3]
        for x in options:
            print "\t :> %s" % x
        choice1 = raw_input("What is your response? :>")
        if ('loser' in choice1) or ('fat' in choice1):
            print "You are sucked into the troll's behaviour and are driven insane"
            print "After three days of insanity, you starve to death"
            dead()
        elif 'care' in choice1:
            print 'The troll cannot feed off of your anger.'
            print 'The troll starves and you recover one piece of the lever from his stomach.'
            change()
            entrywayopen()
            return incomp1 == True
        else:
            unknown()
            change()
            door1(incomp1)
    elif incomp1 == True:
        print 'You already recovered the piece from room 1.'
        entrywayopen()

所以，当调用函数时，我的 incomp1 的值已经是 False。用户必须得到正确的答案，在本例中为elif 语句。最后，我把它交给return incomp1 == True。然而，价值保持不变。我在这个房间策略中的最后一步是为语句if door1(incomp1) and door2(incomp2) and door3(incomp3): 返回一个值True。是什么导致不返回布尔值更改？

Answer 1

关于 Python 布尔表达式的一点点：

• 每个 python 表达式都可以作为布尔值计算
• None、False、0、0.0，空字符串、列表、元组和字典为False；大多数其他对象是True
• 这意味着：你通常可以只写x，而不是x == True，在你的情况下：if incomp1:

如果您正在执行一个函数并且它在没有遇到return 的情况下完成，则将隐式返回None。如果您对其进行布尔比较，它将评估为False。

Answer 2

您需要将“return incomp1 == True”替换为“return True”。然后像这样调用 door1 函数“incomp1 = door1(incomp1)”。 这会将 incomp1 的值更改为函数“True”返回的值。

您也可以将“elif incomp1 == True:”替换为简单的“else”。

您也可以考虑在choice1 = raw_input("What is your response? :>") 中添加一个.lower()。这将使得如果玩家在输入中使用大写字母，它仍然可以正常工作。

def door1(incomp1):
    if incomp1 == False:
        print 'You enter door 1 and find a hideous internet troll.'
        print "The troll says, 'LOOK AT THIS LOSER'"
        options = ["YOU'RE THE LOSER", "I don't care." , "YOUR MOM IS FAT"]
        options2 = [1,2,3]
        for x in options:
            print "\t :> %s" % x
        #choice1 = raw_input("What is your response? :>")
        choice1 = raw_input("What is your response? :>").lower()
        if ('loser' in choice1) or ('fat' in choice1):
            print "You are sucked into the troll's behaviour and are driven insane"
            print "After three days of insanity, you starve to death"
            dead()
        elif 'care' in choice1:
            print 'The troll cannot feed off of your anger.'
            print 'The troll starves and you recover one piece of the lever from his stomach.'
            change()
            entrywayopen()
            return True
        else:
            unknown()
            change()
            door1(incomp1)
    #elif incomp1 == True:
    else:
        print 'You already recovered the piece from room 1.'
        entrywayopen()

incomp1 = door1(incomp1)