【发布时间】：2011-12-31 02:49:02
【问题描述】：
问题陈述： 编写一个 C++ 程序来计算后缀表达式。您的程序应将后缀表达式作为输入，在堆栈的帮助下对其进行处理，并在执行所需的计算后显示结果。
此程序只允许使用以下二元运算符： +, -, *, /, ^ [加减乘除求幂]
如果在处理后缀表达式时发生错误，您的程序应该显示一条有意义的消息，例如： 错误：不允许除以零 错误：__ 运算符需要两个操作数 错误：后缀表达式无效
帮帮我，我的程序出现错误这是我的尝试：
#include<iostream>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<string>
#define MAX_SIZE 20
using namespace std;
template<class T>
class Stack
{
private:
T item[MAX_SIZE];
int top;
public:
Stack()
{
top = -1;
}
void push(T data)
{
if(!this->is_full())
item[++top] = data;
else
{
cout<<"Stack Error"<<endl;
exit(10);
}
}
T pop()
{
if(!this->is_empty())
return item[top--];
else
{
cout<<"Stack is Empty"<<endl;
exit(11);
}
}
int size()
{
return top+1;
}
bool is_empty()
{
if(top==-1)
return true;
else
return false;
}
bool is_full()
{
if(top==MAX_SIZE-1)
return true;
else
return false;
}
void display()
{
for(int i=0; i<this->size(); i++)
{
cout<<item[i]<<" ";
}
cout<<endl;
}
T return_top()
{
return item[top];
}
};
class Convert
{
private:
bool num_flag;
bool tow_digit_flag;
public:
Convert();
string return_with_bracket(string infix);
void to_Postfix(string infix,char postfix[]);
bool prcd(char op1, char op2);
int isOperand(char op);
int isOperator(char op);
bool return_flag()
{
return num_flag;
}
};
Convert::Convert()
{
this->num_flag = false;
this->tow_digit_flag = false;
}
string Convert::return_with_bracket(string infix)
{
return("(" + infix + ")");
}
bool Convert::prcd(char op1, char op2)
{
if((op1=='+' || op1=='-' || op1=='*' || op1=='/') && op2=='(' )
return true;
if(op1=='+' && op2=='+')
return true;
if(op1=='-' && op2=='-')
return false;
if(op1=='-' && op2=='+')
return false;
if(op1=='+' && op2=='-')
return false;
if(op1=='/' && op2=='/')
return false;
if(op1=='/' && (op2=='-' || op2=='+'))
return true;
if(op1=='*' && (op2=='+' || op2=='-'))
return true;
if((op1 == '-' || op1 == '+') && (op2 =='*' || op2 == '/'))
return false;
if((op1=='$' || op1 == '+') && (op2 =='*' || op2 == '/' || op2=='-'))
return true;
if((op1 == '-' || op1 == '+' || op1 =='*' || op1 == '/')&& op2=='^')
return false;
if(op1 == '^' && ( op2 == '+' || op2 =='*' || op2 == '/' || op2=='-'))
return false;
}
int Convert::isOperand(char op)
{
return(op>= '0' && op <= '9');
}
int Convert::isOperator(char op)
{
return(op=='+' || op=='-' || op == '/' || op=='*' || op=='^');
}
void Convert::to_Postfix(string infix, char postfix[])
{
int position, outpos=0;
char c;
int count = 0;
char temp;
char stacktop ;
Stack<char> stack;
for(position = 0; (c = infix[position])!='\0'; position++)
{
if(this->isOperand)
{
postfix[outpos++] = c;
this->num_flag = true;
count++;
if(count>=2)
{
this->tow_digit_flag = true;
}
}
else if(this->isOperator©)
{
count = 0;
if(isOperator(infix[position]) && isOperator(infix[position+1]))
{
cout<<"\aMissing argument in between "<<infix[position]<<" and "<<infix[position+1]
<<" in column "<< position+1<<endl;
exit(9);
}
if(this->prcd(c, stacktop))
{
stacktop=stack.return_top();
stack.push©;
stacktop = c;
}
else
{
while(true)
{
temp = stack.pop();
postfix[outpos++] =temp;
stacktop = stack.return_top();
if(prcd(c, stacktop) || stacktop=='(')
break;
}
stack.push©;
stacktop = stack.return_top();
}
}
else if(c=='(')
{
count = 0;
stack.push©;
stacktop = stack.return_top();
}
else if(c==')')
{
count = 0;
while(1)
{
if(stack.size()==0)
{
cout<<"Warning!! Number of ')' is greater than '('" <<endl;
exit(2);
}
temp = stack.pop();
if(temp!='(')
{
postfix[outpos++] = temp;
}
else
{
break;
}
}
stacktop =stack.return_top();
}
else
{
cout<<"Invalid input";
exit(3);
}
if(infix[position]==')' && infix[position+1]=='(')
{
stack.push('*');
stacktop = stack.return_top();
}
}
if(stack.size()!=0)
{
cout<<"Warning!!Number of '(' is greater than ')'"<<endl;
// exit(6);
}
if(!this->return_flag())
{
cout<<"You must Enter Numeric value for calculation"<<endl;
cout<<"This program cannot perform operations on variables";
exit(5);
}
if(this->tow_digit_flag)
{
cout<<"Sory! Althoug u may have entered right string"<<endl;
cout<<"this program is only for single digit operation"<<endl;
exit(8);
}
postfix[outpos] = '\0';
}
class Evaluate
{
public:
double eval(char expr[], Convert &Wink;
double oper(int symb, double op1, double op2);
};
double Evaluate::oper(int symb, double op1, double op2)
{
switch(symb)
{
case '+':
return (op1 + op2);
case '-':
return (op1 - op2);
case '*':
return (op1 * op2);
case '/':
return (op1 / op2);
case '^':
return (pow(op1, op2));
}
}
double Evaluate::eval(char expr[],Convert &convert)
{
int c, position;
char temp1;
int count = 0;
double opnd1, opnd2, value;
Stack<double> stack;
for(position = 0; (c = expr[position])!='\0'; position++)
{
if(convert.isOperand©)
{
temp1 = double(c-'0');
stack.push(temp1);
}
else
{
opnd2 = stack.pop();
if(stack.size()==0)
{
cout<<"This program cannot process unary operation";
exit(1);
}
opnd1 = stack.pop();
value = oper(c, opnd1, opnd2);
stack.push(value);
}
}
if(stack.size()>=2)
{
cout<<"Sory! this program cannot calculate this"<<endl;
cout<<"Enter +, *, /, - or ^ between bracket"<<endl;
exit(4);
}
return (stack.pop());
}
int main()
{
Convert convert;
Evaluate evaluate;
string bracketted_infix;
char infix[50], postfix[50];
char choice;
while(1)
{
cout<<"Enter operation: ";
cin>>infix;
cout<<endl;
cout<<"Entered operation: "<<infix<<endl;
bracketted_infix = convert.return_with_bracket(infix);
convert.to_Postfix(bracketted_infix, postfix);
cout<<"Equivalent Postfix operation: "<<postfix<<endl;
cout<<"RESULT: ";
cout<<evaluate.eval(postfix, convert);
cout<<"\nCalculate another operation?(y/n) ";
cin>>choice;
cout<<endl;
if(choice=='n')
break;
}
return 0;
}
【问题讨论】：
-
你遇到了什么错误？
-
你能发布你得到的错误吗？
-
您在文字处理应用程序中编程？
(c)变成©... -
你能发布一个有问题的小程序吗？它甚至可以帮助您自己发现问题。 sscce.org
-
尝试使用std::stack。 msdn.microsoft.com/en-us/library/56fa1zk5%28v=vs.71%29.aspx 而不是编写自己的课程。至少它会简化你的调试。
标签： c++ stack postfix-notation rpn