根据另一个列表的顺序对一个列表进行排序[重复]

Question

请参阅以下 2 个列表：

如果我将猫及其年龄附加到两个不同的列表中，我如何对其进行排序，以便在打印最老猫的年龄时，也打印卢克，而在打印最小猫的年龄时，罗尼也被打印出来。

cats = ["ronny", "brodie", "fraise", "luke"]
age = [5, 6, 7, 11]

age.sort()
print("The age of the oldest cat is {}. This cat is {}".format(age[-1], 
cats[THE OLDEST CAT]))
print("The age of the youngest cat is {}. This cat is {}".format(age[0], 
cats[THE YOUNGEST CAT]))

我该怎么做？

Answer 1

你可以zip这两个列表，然后在它们上应用sorted，这样与他们年龄的猫一起在一个元组中。如下所示：

In [60]: cats = ["ronny", "brodie", "fraise", "luke"]
    ...: age = [5, 6, 7, 11]
    ...: cats_by_age = sorted(zip(age, cats))
    ...: 
    ...: print("The age of the oldest cat is {}. This cat is {}".format(*cats_by_age[-1]))
    ...: print("The age of the youngest cat is {}. This cat is {}".format(*cats_by_age[0]))
    ...: 
The age of the oldest cat is 11. This cat is luke
The age of the youngest cat is 5. This cat is ronny