【发布时间】:2016-05-01 20:51:13
【问题描述】:
我是编程初学者,刚刚学习了新概念并开始编写矩阵乘法代码,但我对指针和其他内容感到困惑,所以我在这里上传我的代码以寻求指导。
#include <stdio.h>
#include <stdlib.h>
int **matrixMultiply(int A[][8], int B[][8], int row);
int main() {
int **A = allocate_matrix(A, 8, 8);
int **B = allocate_matrix(B, 8, 8);
int i, j;
for (i = 0; i < 8; i++) {
for (j = 0; j < 8; j++) {
A[i][j] = i + j;
A[i][j] = i + j;
}
}
int **C = allocate_matrix(C, 8, 8);
C = matrixMultiply(A, B, 8);
return 0;
}
int **matrixMultiply(int A[][8], int B[][8], int row) {
int **C = allocate_matrix(C, row, row);
if (row == 1) {
C[1][1] = A[1][1] * B[1][1];
} else {
int a11[row/2][row/2], a12[row/2][row/2], a21[row/2][row/2], a22[row/2][row/2];
int b11[row/2][row/2], b12[row/2][row/2], b21[row/2][row/2], b22[row/2][row/2];
int **c11 = allocate_matrix(c11, row/2, row/2);
int **c12 = allocate_matrix(c12, row/2, row/2);
int **c21 = allocate_matrix(c21, row/2, row/2);
int **c22 = allocate_matrix(c22, row/2, row/2);
int i, j;
for (i = 0; i < row/2; i++) {
for (j = 0; j < row/2; j++) {
a11[i][j] = A[i][j];
a12[i][j] = A[i][j + (row/2)];
a21[i][j] = A[i + (row/2)][j];
a22[i][j] = A[i + (row/2)][j + (row/2)];
b11[i][j] = B[i][j];
b12[i][j] = B[i][j + (row/2)];
b21[i][j] = B[i + (row/2)][j];
b22[i][j] = B[i + (row/2)][j + (row/2)];
c11[i][j] = C[i][j];
c12[i][j] = C[i][j + (row/2)];
c21[i][j] = C[i + (row/2)][j];
c22[i][j] = C[i + (row/2)][j + (row/2)];
}
}
c11 = addmatrix(matrixMultiply(a11, b11, row/2),
matrixMultiply(a12, b21, row/2), c11, row/2);
c12 = addmatrix(matrixMultiply(a11, b12, row/2),
matrixMultiply(a22, b22, row/2), c12, row/2);
c21 = addmatrix(matrixMultiply(a21, b11, row/2),
matrixMultiply(a22, b21, row/2), c21, row/2);
c22 = addmatrix(matrixMultiply(a21, b12, row/2),
matrixMultiply(a22, b22, row/2), c22, row/2);
// missing code???
return C;
}
}
int **allocate_matrix(int **matrix, int row, int column) {
matrix = (int **)malloc(row * sizeof(int*));
int i;
for (i = 0; i < row; i++) {
matrix[row] = (int *)malloc(row * sizeof(int));
}
return matrix;
}
void deallocate_matrix(int **matrix, int row) {
int i;
for (i = 0; i < row; i++) {
free(matrix[row]);
}
free(matrix);
}
int **addMatrix(int **a, int **b, int **c, int row) {
int i, j;
for (i = 0; i < row; i++) {
for (j = 0; j < row; j++) {
c[i][j] = a[i][j] + b[i][j];
}
}
return c;
}
【问题讨论】:
-
编辑描述并添加您面临的问题。
-
改变矩阵[row] = (int *)malloc(row * sizeof(int)); this to matrix[row] = (int *)malloc(column * sizeof(int));您没有遇到问题,因为行和列都是 8。如果列多于行,您的代码就会有问题。
-
指针不被称为“数组”是有充分理由的,反之亦然。
int **是“指向指针的指针”,而int (*)[]是“指向数组的指针”。 -
将
matrix参数传递给allocate_matrix是没有意义的。 -
@Sri.U:不要在 C 中转换
void *!
标签: c recursion matrix-multiplication divide-and-conquer