【问题标题】:Matrix Multiplication using divide and conquer approach [closed]使用分治法的矩阵乘法[关闭]
【发布时间】:2016-05-01 20:51:13
【问题描述】:

我是编程初学者,刚刚学习了新概念并开始编写矩阵乘法代码,但我对指针和其他内容感到困惑,所以我在这里上传我的代码以寻求指导。

#include <stdio.h>
#include <stdlib.h>

int **matrixMultiply(int A[][8], int B[][8], int row);

int main() {
    int **A = allocate_matrix(A, 8, 8);
    int **B = allocate_matrix(B, 8, 8);

    int i, j;
    for (i = 0; i < 8; i++) {
        for (j = 0; j < 8; j++) {
            A[i][j] = i + j;
            A[i][j] = i + j;
        }
    }

    int **C = allocate_matrix(C, 8, 8);
    C = matrixMultiply(A, B, 8);

    return 0;
}

int **matrixMultiply(int A[][8], int B[][8], int row) {
    int **C = allocate_matrix(C, row, row);
    if (row == 1) {
        C[1][1] = A[1][1] * B[1][1];
    } else {
        int a11[row/2][row/2], a12[row/2][row/2], a21[row/2][row/2], a22[row/2][row/2];
        int b11[row/2][row/2], b12[row/2][row/2], b21[row/2][row/2], b22[row/2][row/2];
        int **c11 = allocate_matrix(c11, row/2, row/2);
        int **c12 = allocate_matrix(c12, row/2, row/2);
        int **c21 = allocate_matrix(c21, row/2, row/2);
        int **c22 = allocate_matrix(c22, row/2, row/2);

        int i, j;
        for (i = 0; i < row/2; i++) {
            for (j = 0; j < row/2; j++) {
                a11[i][j] = A[i][j];
                a12[i][j] = A[i][j + (row/2)];
                a21[i][j] = A[i + (row/2)][j];
                a22[i][j] = A[i + (row/2)][j + (row/2)];
                b11[i][j] = B[i][j];
                b12[i][j] = B[i][j + (row/2)];
                b21[i][j] = B[i + (row/2)][j];
                b22[i][j] = B[i + (row/2)][j + (row/2)];
                c11[i][j] = C[i][j];
                c12[i][j] = C[i][j + (row/2)];
                c21[i][j] = C[i + (row/2)][j];
                c22[i][j] = C[i + (row/2)][j + (row/2)];
            }
        }

        c11 = addmatrix(matrixMultiply(a11, b11, row/2),
                        matrixMultiply(a12, b21, row/2), c11, row/2);
        c12 = addmatrix(matrixMultiply(a11, b12, row/2),
                        matrixMultiply(a22, b22, row/2), c12, row/2);
        c21 = addmatrix(matrixMultiply(a21, b11, row/2),
                        matrixMultiply(a22, b21, row/2), c21, row/2);
        c22 = addmatrix(matrixMultiply(a21, b12, row/2),
                        matrixMultiply(a22, b22, row/2), c22, row/2);

        // missing code???
        return C;
    }
}

int **allocate_matrix(int **matrix, int row, int column) {
    matrix = (int **)malloc(row * sizeof(int*));
    int i;
    for (i = 0; i < row; i++) {
        matrix[row] = (int *)malloc(row * sizeof(int));
    }
    return matrix;
}

void deallocate_matrix(int **matrix, int row) {
    int i;
    for (i = 0; i < row; i++) {
        free(matrix[row]);
    }
    free(matrix);
}

int **addMatrix(int **a, int **b, int **c, int row) {
    int i, j;
    for (i = 0; i < row; i++) {
        for (j = 0; j < row; j++) {
            c[i][j] = a[i][j] + b[i][j];
        }
    }
    return c;
}

【问题讨论】:

  • 编辑描述并添加您面临的问题。
  • 改变矩阵[row] = (int *)malloc(row * sizeof(int)); this to matrix[row] = (int *)malloc(column * sizeof(int));您没有遇到问题,因为行和列都是 8。如果列多于行,您的代码就会有问题。
  • 指针不被称为“数组”是有充分理由的,反之亦然。 int ** 是“指向指针的指针”,而 int (*)[] 是“指向数组的指针”。
  • matrix 参数传递给allocate_matrix 是没有意义的。
  • @Sri.U:不要在 C 中转换 void *

标签: c recursion matrix-multiplication divide-and-conquer


【解决方案1】:

我重新格式化了您的代码,以便对其进行分析。缩进 4 个空格,在二元运算符周围、,; 分隔符之后以及关键字和( 之间插入空格,这大大提高了可读性。

matrixMultiply 函数中似乎缺少代码:您分配了结果矩阵 C,但您使用它作为输入来初始化中间矩阵 c11c21c21 和 @987654329 @,并且从不将任何内容实际存储到 C 中,除了琐碎的 1x1 情况。

矩阵乘法代码似乎超出了这个范围,该函数采用int A[][8], int B[][8] 类型的2 个参数,但您使用定义为int a11[row/2][row/2] 的本地数组a11b22 递归调用它。这些类型都不一样,我都不知道代码是怎么编译的。

在矩阵分配代码中,分配大小不正确的行row 而不是column。您应该为此使用calloc,以便将矩阵初始化为0,而且您根本不应该传递初始参数:

int **allocate_matrix(int row, int column) {
    int **matrix = malloc(row * sizeof(*matrix));
    for (int i = 0; i < row; i++) {
        matrix[i] = calloc(column, sizeof(*matrix[row]));
    }
    return matrix;
}

第二次子矩阵乘法也有错误,应该是

    c12 = addmatrix(matrixMultiply(a11, b12, row/2),
                    matrixMultiply(a12, b22, row/2), c12, row/2);

此外,您永远不会释放用于中间结果的临时矩阵。与 java 不同,C 没有垃圾收集器,您有责任在不再需要它们时释放内存块,以免它们变得不可访问。

这是一个更正的版本,具有打印矩阵数据和验证矩阵乘法正确性的额外功能。我添加了计时:递归方法比直接方法慢很多,主要是因为中间结果的所有额外分配/释放。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

int **matrix_allocate(int row, int column) {
    int **matrix = malloc(row * sizeof(*matrix));
    for (int i = 0; i < row; i++) {
        matrix[i] = calloc(column, sizeof(*matrix[i]));
    }
    return matrix;
}

void matrix_free(int **matrix, int row) {
    for (int i = 0; i < row; i++) {
        free(matrix[i]);
    }
    free(matrix);
}

void matrix_print(const char *str, int **a, int row) {
    int min, max, w = 0, n1, n2, nw;
    min = max = a[0][0];
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < row; j++) {
            if (min > a[i][j])
                min = a[i][j];
            if (max < a[i][j])
                max = a[i][j];
        }
    }
    n1 = snprintf(NULL, 0, "%d", min);
    n2 = snprintf(NULL, 0, "%d", max);
    nw = n1 > n2 ? n1 : n2;

    for (int i = 0; i < row; i++) {
        if (i == 0)
            w = printf("%s = ", str);
        else
            printf("%*s", w, "");

        for (int j = 0; j < row; j++) {
            printf(" %*d", nw, a[i][j]);
        }
        printf("\n");
    }
    fflush(stdout);
}

int **matrix_add(int **a, int **b, int row, int deallocate) {
    int **c = matrix_allocate(row, row);
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < row; j++) {
            c[i][j] = a[i][j] + b[i][j];
        }
    }
    if (deallocate & 1) matrix_free(a, row);
    if (deallocate & 2) matrix_free(b, row);

    return c;
}

int **matrix_multiply(int **A, int **B, int row, int deallocate) {
    int **C = matrix_allocate(row, row);
    if (row == 1) {
        C[0][0] = A[0][0] * B[0][0];
    } else {
        int row2 = row / 2;
        int **a11 = matrix_allocate(row2, row2);
        int **a12 = matrix_allocate(row2, row2);
        int **a21 = matrix_allocate(row2, row2);
        int **a22 = matrix_allocate(row2, row2);
        int **b11 = matrix_allocate(row2, row2);
        int **b12 = matrix_allocate(row2, row2);
        int **b21 = matrix_allocate(row2, row2);
        int **b22 = matrix_allocate(row2, row2);

        for (int i = 0; i < row2; i++) {
            for (int j = 0; j < row2; j++) {
                a11[i][j] = A[i][j];
                a12[i][j] = A[i][j + row2];
                a21[i][j] = A[i + row2][j];
                a22[i][j] = A[i + row2][j + row2];
                b11[i][j] = B[i][j];
                b12[i][j] = B[i][j + row2];
                b21[i][j] = B[i + row2][j];
                b22[i][j] = B[i + row2][j + row2];
            }
        }

        int **c11 = matrix_add(matrix_multiply(a11, b11, row2, 0),
                               matrix_multiply(a12, b21, row2, 0), row2, 1+2);
        int **c12 = matrix_add(matrix_multiply(a11, b12, row2, 1),
                               matrix_multiply(a12, b22, row2, 1), row2, 1+2);
        int **c21 = matrix_add(matrix_multiply(a21, b11, row2, 2),
                               matrix_multiply(a22, b21, row2, 2), row2, 1+2);
        int **c22 = matrix_add(matrix_multiply(a21, b12, row2, 1+2),
                               matrix_multiply(a22, b22, row2, 1+2), row2, 1+2);

        for (int i = 0; i < row2; i++) {
            for (int j = 0; j < row2; j++) {
                C[i][j] = c11[i][j];
                C[i][j + row2] = c12[i][j];
                C[i + row2][j] = c21[i][j];
                C[i + row2][j + row2] = c22[i][j];
            }
        }
        matrix_free(c11, row2);
        matrix_free(c12, row2);
        matrix_free(c21, row2);
        matrix_free(c22, row2);
    }
    if (deallocate & 1) matrix_free(A, row);
    if (deallocate & 2) matrix_free(B, row);

    return C;
}

int **matrix_multiply_direct(int **A, int **B, int row, int deallocate) {
    int **C = matrix_allocate(row, row);
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < row; j++) {
            int x = 0;
            for (int k = 0; k < row; k++) {
                x += A[i][k] * B[k][j];
            }
            C[i][j] = x;
        }
    }
    if (deallocate & 1) matrix_free(A, row);
    if (deallocate & 2) matrix_free(B, row);

    return C;
}

int main(int argc, char **argv) {
    int n = argc < 2 ? 8 : atoi(argv[1]);
    int **A = matrix_allocate(n, n);
    int **B = matrix_allocate(n, n);

    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            A[i][j] = i + j;
            B[i][j] = i + j;
        }
    }

    matrix_print("A", A, n);
    matrix_print("B", B, n);

    if ((n & (n - 1)) == 0) {
        /* recursive method can be applied only to powers of 2 */
        clock_t ticks = -clock();
        int **C = matrix_multiply(A, B, n, 0);
        ticks += clock();
        matrix_print("C = A * B", C, n);
        printf("%d ticks\n", ticks);
        matrix_free(C, n);
    }

    clock_t ticks = -clock();
    int **D = matrix_multiply_direct(A, B, n, 1+2);
    ticks += clock();

    matrix_print("D = A * B", D, n);
    printf("%d ticks\n", ticks);
    matrix_free(D, n);

    return 0;
}

【讨论】:

  • 感谢@chqrlie,代码中包含许多要学习的东西。
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