检查 NSString 的最后一个字符是否为数字

Question

是否可以看到以未知长度的数字结尾的字符串？

1. “字符串 1”-> 1
2. “字符串 4356”-> 4356
3. “字符串”-> 无

如果是这样，我如何确定这个数字？

Answer 1

要测试字符串是否以数字结尾，可以使用NSPredicate，例如：

NSPredicate endsNumerically = [NSPredicate predicateWithFormat:@"SELF matches %@", @"\\d+$"];
[endsNumerically evaluateWithObject:string]; // returns TRUE if predicate succeeds

NSScanner 有时可用于从字符串中提取内容，但它不会向后扫描。您可以定义一个 Gnirts（反向字符串）类并将其与 NSScanner 一起使用，但这可能比它的价值更麻烦。

我希望使用的 NSString 的 rangeOfCharacterFromSet:options: 只查找单个字符（就像 strchr and strrchr，如果您熟悉 C 的话），但我们可以滚动自己的返回连续字符范围从一组（有点像strspn）作为category 上的NSString。在此过程中，让我们包含返回子字符串而不是范围的方法。

RangeOfCharacters.h：

@interface NSString (RangeOfCharacters)
/* note "Characters" is plural in the methods. It has poor readability, hard to 
 * distinguish from the rangeOfCharacterFromSet: methods, but it's standard Apple 
 * convention.
 */
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet;
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask;
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range;

// like the above, but return a string rather than a range
-(NSString*)substringFromSet:(NSCharacterSet*)aSet;
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask;
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range;
@end

RangeOfCharacters.m：

@implementation NSString (RangeOfCharacters)
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet {
    return [self rangeOfCharactersFromSet:aSet options:0];
}

-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask {
    NSRange range = {0,[self length]};
    return [self rangeOfCharactersFromSet:aSet options:mask range:range];
}

-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range {
    NSInteger start, curr, end, step=1;
    if (mask & NSBackwardsSearch) {
        step = -1;
        start = range.location + range.length - 1;
        end = range.location-1;
    } else {
        start = range.location;
        end = start + range.length;
    }
    if (!(mask & NSAnchoredSearch)) {
        // find first character in set
        for (;start != end; start += step) {
            if ([aSet characterIsMember:[self characterAtIndex:start]]) {
#ifdef NOGOTO
                break;
#else
                // Yeah, a goto. If you don't like them, define NOGOTO.
                // Method will work the same, it will just make unneeded
                // test whether character at start is in aSet
                goto FoundMember;
#endif
            }
        }
#ifndef NOGOTO
        goto NoSuchMember;
#endif
    }
    if (![aSet characterIsMember:[self characterAtIndex:start]]) {
    NoSuchMember:
        // no characters found within given range
        range.location = NSNotFound;
        range.length = 0;
        return range;
    }

FoundMember:
    for (curr = start; curr != end; curr += step) {
        if (![aSet characterIsMember:[self characterAtIndex:curr]]) {
            break;
        }
    }
    if (curr < start) {
        // search was backwards
        range.location = curr+1;
        range.length = start - curr;
    } else {
        range.location = start;
        range.length = curr - start;
    }
    return range;
}

-(NSString*)substringFromSet:(NSCharacterSet*)aSet {
    return [self substringFromSet:aSet options:0];
}

-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask  {
    NSRange range = {0,[self length]};
    return [self substringFromSet:aSet options:mask range:range];
}
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range {
    NSRange range = [self rangeOfCharactersFromSet:aSet options:mask range:range];
    if (NSNotFound == range.location) {
        return nil;
    }
    return [self substringWithRange:range]; 
}
@end

使用新类别检查字符串是否以数字结尾或提取数字：

NSString* number = [string substringFromSet:[NSCharacterSet decimalDigitCharacterSet] 
                             options:NSBackwardsSearch|NSAnchoredSearch];
if (number != nil) {
    return [number intValue];
} else {
    // string doesn't end with a number.
}

最后，您可以使用第三方正则表达式库，例如RegexKit 或RegexkitLite。

Answer 2

我无法让上面的NSPredicate 代码正常工作，尽管它看起来应该正常工作。相反，我用

完成了同样的事情

if ([string rangeOfString:@"\\d+$" options:NSRegularExpressionSearch].location != NSNotFound) {
    // string ends with a number
}

致this answer。