拆分数字/显示总和

Question

---

到目前为止，这是我的代码，但是当我运行 sum_of_digits("45ggd") 时，我得到以下结果：

数字的总和是9。

提取的非数字为：['ggd']

9

如我所愿：

数字的总和是 4 + 5。

提取的非数字为：['g', 'g', 'd']
9

def sum_of_digits(string):

    sum_digits = 0
    extracted_alphas = ""

    for char in string:
        if char.isdigit() == True:
            sum_digits += int(char)
    
        elif char.isalpha():
            extracted_alphas += char
          
    else:
        if (len(string)==0):
            sum_digits = "" 
            print("Empty string entered!")     
            return 0 

        elif char.isdigit() == False:
            print("The sum of digits operation could not detect a digit!")
            print("The returned input letters are: ['" + str(extracted_alphas) + "']")
            return 0

    print("The sum of digits is", sum_digits,".")
    print("The extracted non-digits are: ['" + str(extracted_alphas) + "']")
    return sum_digits

Answer 1

要将数字的总和打印为表达式（如 4+5），您需要使用给定字符串的数字构建一个字符串。要打印以指定格式显示的字母，您需要将它们存储在一个列表中。

def sum_of_digits(string):

    sum_digits = ""
    extracted_alphas = []
    
    if (len(string)==0):
        sum_digits = "" 
        print("Empty string entered!")     
        return 0

    for char in string:
        if char.isdigit() == True:
            sum_digits += char+"+"
    
        elif char.isalpha():
            extracted_alphas.append(char)

    if len(sum_digits) == 0:
        print("The sum of digits operation could not detect a digit!")
        print("The returned input letters are: ", extracted_alphas)
        return 0
    
    sum_digits = sum_digits[:-1]
    print("The sum of digits is", sum_digits,".")
    print("The extracted non-digits are: ", extracted_alphas)
    return sum_digits