创建两个不同的随机变量[重复]答案

【问题标题】：Create two different Random variable [duplicate]创建两个不同的随机变量[重复]
【发布时间】：2021-08-07 14:19:25
【问题描述】：

我正在制作一种扑克游戏，您可以在其中与 ai 对战，并且你们都会得到一组随机数。在为它创建方法时，我注意到程序总是为两者创建相同的数组。

public short[] GenerateNumbers(short[] playerNumbers)  //The generate numbers method creates an array of random numbers
        {
            Random randNumb = new Random();  //Creation of a random type object called randNumb. This object is the one that creates the random numbers in the array

            playerNumbers = new short[5];  //Stating the length of the player's array

            for (int i = 0; i < playerNumbers.Length; i++)  //This loop creates random numbers for every position in the array
            {
                playerNumbers[i] = (short)randNumb.Next(1, 9);
            }

            playerOneHand = playerNumbers;

            return playerOneHand;
        }

        public short[] GenerateAINumbers(short[] aiNumbers)  //The generate numbers method creates an array of random numbers
        {
            Random randAINumb = new Random();  //Creation of a random type object called randNumb. This object is the one that creates the random numbers in the array

            aiNumbers = new short[5];  //Stating the length of the player's array

            for (int j = 0; j < aiNumbers.Length; j++)  //This loop creates random numbers for every position in the array
            {
                aiNumbers[j] = (short)randAINumb.Next(1, 9);
            }

            aiHand = aiNumbers;

            return aiHand;
        }

【问题讨论】：

这能回答你的问题吗？ Random.Next returns always the same values（使用的搜索词：c# random creates same results）
在发帖前请阅读MSDN！

标签： c#

【解决方案1】：

您可以创建实例级别的随机对象：

private Random rnd = new Random();

public short[] GenerateNumbers(short[] playerNumbers) {...}

public short[] GenerateAINumbers(short[] aiNumbers) {...}

您可以在方法中使用这个 rnd 对象，而不是总是创建一个新对象。

【讨论】：