【发布时间】:2020-08-09 18:57:27
【问题描述】:
from concurrent.futures import ProcessPoolExecutor
import os
import time
def parInnerLoop(item):
a = 2+item
print(f'A. {a} Processing {os.getpid()} done on {item}\n')
exec(open('mainWork.py').read())
print(f'D. {a} Processing {os.getpid()} done on {item}\n')
def main():
with ProcessPoolExecutor(max_workers=4) as executor:
for itemNo in range(10):
executor.submit(parInnerLoop, itemNo)
print('done')
if __name__ == '__main__':
main()
mainWork.py
print(f'B. {a} Processing {os.getpid()} done on {item}\n')
a = 12
print(f'C. {a} Processing {os.getpid()} done on {item}\n')
错误:
Error in atexit._run_exitfuncs:
Traceback (most recent call last):
File "D:\Program Files\Python\Python37\Lib\concurrent\futures\process.py", line 101, in _python_exit
thread_wakeup.wakeup()
File "D:\Program Files\Python\Python37\Lib\concurrent\futures\process.py", line 89, in wakeup
self._writer.send_bytes(b"")
File "D:\Program Files\Python\Python37\Lib\multiprocessing\connection.py", line 183, in send_bytes
self._check_closed()
File "D:\Program Files\Python\Python37\Lib\multiprocessing\connection.py", line 136, in _check_closed
raise OSError("handle is closed")
OSError: handle is closed
问题:
- 错误,出现在程序末尾。
- 我想将
mainWork.py的所有代码作为parInnerLoop的一部分执行,这样a值的变化应该反映在parInnerLoop和mainWork.py中,反之亦然。我得到如下输出。a的值不会改变打印以D. ...开头的位置,我希望它是 12。
项目0的输出
A. 2 Processing 19784 done on 0
B. 2 Processing 19784 done on 0
C. 12 Processing 19784 done on 0
D. 2 Processing 19784 done on 0
发生了什么事?请帮忙。
我最终想要实现的目标:以不同的设置并行运行相同的代码,而不会相互干扰
额外:
- 我测试了 ProcessPoolExecutor 工作正常,如图here。
- 我使用以下代码测试了
exec(open('run.py').read())按预期工作:
main.py
def myFun():
a = 1
b = 2
print(a)
exec(open('run.py').read())
#execfile("run.py")
print(a)
print(b)
print(c)
def main():
myFun()
if __name__ == '__main__':
main()
运行.py
a = a+5
b = 10
c = 15
输出
1
6
10
15
【问题讨论】:
-
我在 Linux 上使用 3.7.6 时遇到了同样的问题。这似乎是一个开放的错误
-
@nokada,我在 Windows 上使用 Python 3.7.8 时遇到了同样的问题。看起来像,但尚未修复。
-
更新到 python 3.9+ 来解决这个问题
标签: python python-3.x parallel-processing concurrent.futures