Mysql ORDER BY COUNT(*) 获取最旧的行

Question

你能帮帮我吗？我愿意

1) 检查来自 tb_pre_sale 的 id 是否在 seler_0 列上不存在或存在但至少不重复 2 次​​p>

2) 获取最旧的

谢谢！

 SELECT DISTINCT seller_0 
 FROM tb_pre_sale 
 WHERE seller_0 !=? 
 GROUP BY id 
 ORDER BY COUNT(*) < ? DESC

Answer 1

 SELECT seller_0 
 FROM tb_pre_sale 
 WHERE seller_0 !=? 
 GROUP BY  seller_0 
 HAVING COUNT(*) < ? ORDER BY seller_0 DESC