【发布时间】:2019-02-08 19:41:17
【问题描述】:
早上好 我有一个项目,我必须编写一个看起来像这样的游戏: http://www.apppicker.com/apps/1055267582/1010-hex-fit--block-puzzle-mania-archanoid-pixduel-plus-saga-free-game? 而且我必须编写没有课程(“课程”)的游戏,因为我的学校不希望我这样做:(。
现在,我已经完美地绘制了网格,但不幸的是,我似乎无法让我的棋子走在精确的六边形“正方形”上,因为它不是传统的网格。 有人可以帮我吗? 以及如何为数组分配值?
如果您对此问题无能为力,至少可以指导我做其他事情吗?
(我在帖子的最后一个版本中稍微更改了我的程序以使其更清晰)
提前感谢您的宝贵时间。
from tkinter import *
from random import choice #for colors
beige = (255,228,196)
def dessus(evt): #mouse on hexagonal pawn
forme = "arrow"
if x_pion - 50 < evt.x < x_pion + 50 and y_pion - 100 < evt.y < y_pion + 100:
forme = "fleur"
# print(x_pion , y_pion)
can.config(cursor = forme)
def glisser(evt): #mouse dragging the hexagonal pawn
global x, y
if x == -1 :
if x_pion - 50 < evt.x < x_pion + 50 and y_pion - 100 < evt.y < y_pion + 100:
x, y = evt.x, evt.y
else :
delta_x, delta_y = evt.x - x, evt.y - y
can.coords(pion, x_pion + delta_x, y_pion + delta_y)
def coord_case(x_pos,y_pos):
# return hexagonal coordinates spot from the game board
coord_x = x_pos//c
coord_y = y_pos//c
print(x_pos, y_pos)
return coord_x, coord_y
def coord_image(x_pos,y_pos):
# return the coordinates of the image
x = c * x_pos + dc
y = c * y_pos + dc
return x, y
def deposer(evt): #put/release the image (hexagonal pawn) on the screen
global x_pion, y_pion, x
if x != -1:
x_pion, y_pion = x_pion + evt.x - x, y_pion + evt.y - y
x =- 1
def hexagone(origine, c): #draws the hexagones
seg = c / 4
x, y = origine[0], origine[1]
# hexagone
can.create_polygon(x,y+seg, x+2*seg,y, x+c,y+seg, x+c,y+3*seg ,x+2*seg,y+c ,x,y+3*seg, x,y+seg,
outline='black', width=1, fill="beige")
def ligne_d_hexagones(x, y, c, n): #draws the hexagonal lines
i = 0
seg = c / 4
while i < n:
hexagone((x + 2, y + 2), c) # +2 :
i += 1
x += 4.25 * seg
def damier(c, nl, nc):
#finally draws everything (the hexagonal game board)
x = 2.08 # commencera la ligne
y = 0.02
i = 1
for i in range(nc-1):
ligne_d_hexagones(x * c, y * c, c, nc // 2)
i+=1
y = y + 0.79
if i < 5:
nc = nc + 2
x = x - 0.52
if i == 5:
nc = nc - 2
x = x + 0.52
if i > 5:
nc = nc - 2
x = x + 0.52
c = 70 # size of the hexagones from the board
nl = 10 # number of lines
nc = 10 # number of columns (this valuer will change)
dc = c//2
fen = Tk()
fen.title("HEX1010")
can = Canvas(fen, width=1000, height=700)
can.pack(side=TOP)
damier(c, nl, nc)
can.grid()
x, y = -1, -1
f_pion = PhotoImage(file="HEX.png")
x_pion, y_pion = 600, 600
pion = can.create_image(x_pion, y_pion,image=f_pion)
x, y, num = -1, -1, -1
can.bind('<B1-Motion>',glisser)
can.bind('<ButtonRelease-1>',deposer)
can.bind('<Motion>',dessus)
fen.mainloop()
【问题讨论】:
-
您应该提供指向
HEX.png的链接 -
@ReblochonMasque 您好,很抱歉给您带来不便。在这里,现在可以访问 HEX.png。非常感谢您的回复。
-
@ReblochonMasque 我也稍微改变了我的程序,只有一个棋子而不是 3 个......它更简单
标签: grid-layout hexagonal-tiles