用联合连接子查询（一个表有两个条件）

Question

我有 1 张桌子，有 2 种不同的条件。 我要呈现 AR，年度，AR / 年度 * 365。

下面的代码可以运行

select AR, AR*365 
from (select sum(total_amount) AR
from invoices
where issue_date is not null and closed_at is null
and issue_date <= 'January 1,2020' and issue_date <DATEADD (DAY, 1, 'December 31,2020') 
UNION
select sum(total_amount)
from invoices
where closed_at <= 'January 1,2020' and closed_at <DATEADD (DAY, 1, 'December 31,2020')
)x group by AR;

结果：

   AR
1,895.23            15,903,040.94
691,758.95          5,804,609,943.1

然后我想显示 AR、年度、AR/annual*365 但出现错误：

select AR, annual, AR/annual*365 from
(select sum(total_amount) AR
from invoices
where issue_date is not null and closed_at is null
and issue_date <= 'January 1,2020' and issue_date <DATEADD (DAY, 1, 'December 31,2020')
UNION
select sum(total_amount) annual
from invoices
where closed_at <= 'January 1,2020' and closed_at <DATEADD (DAY, 1, 'December 31,2020'))x group by         
AR;

当你想显示“年度”的年度值时，第一行/第一次选择无法读取...

但是当我们从第一行删除“annual”时，可以读取annual。

我希望读取第一行/第一个选择中的“年度”，以便可以使用其他值进行计算。

有人知道怎么解决吗？

Answer 1

您可以按如下方式使用条件聚合：

Select AR, annual, AR/annual*365 from
(select sum(case when issue_date is not null and closed_at is null
                  and issue_date <= 'January 1,2020' 
                  and issue_date <DATEADD (DAY, 1, 'December 31,2020') 
                 then total_amount end) AR,
        sum(case when closed_at <= 'January 1,2020' 
                  and closed_at <DATEADD (DAY, 1, 'December 31,2020') 
                 then total_amount end) as annual
   from invoices) t

annual 可能为 0，并且它用于除法，因此请在此处使用适当的逻辑。