如何在 SQL PIVOT 中排序答案

【问题标题】：How to ORDER BY in SQL PIVOT如何在 SQL PIVOT 中排序
【发布时间】：2012-11-25 03:43:15
【问题描述】：

我目前有这个查询使用 PIVOT 生成这样的表：

  USER  |  DEC  |  NOV  |  OCT
---------------------------------
  bob   |   3   |   5   |   2
  jon   |   7   |   0   |   1 
  tim   |   4   |   2   |   6

我想做但看起来有点牵强的是ORDER BY 的结果由DEC 值递减。

这是查询：

with Mth (st, nd) as ( 
  select DATEADD (M, datediff (m, 0,'2012-09-01'), 0), 
         DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)   
  union all 
  select DATEADD (m, 1, st), 
         DATEADD (m, 1, nd) 
  from Mth 
  where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
) 
select * 
from 
( 
  select MONTH(Mth.st) Month, 
      U.USER, 
      COUNT(S.QRY_ID) Searches 
  FROM Mth 
  LEFT JOIN SEARCHES S 
    on Mth.st <= S.CREATED 
    and Mth.nd > S.CREATED 
  LEFT JOIN MEMBERS U 
    on U.AID = S.AID 
  GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
) src 
pivot 
( 
  sum(searches) 
  for month in ([12],[11],[10]) 
) piv

piv ORDER BY piv.Searches 会报错，是否可以指定列？

【问题讨论】：

标签： sql sql-server tsql pivot

【解决方案1】：

试试这个：

with Mth (st, nd) as ( 
  select DATEADD (M, datediff (m, 0,'2012-09-01'), 0), 
         DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)   
  union all 
  select DATEADD (m, 1, st), 
         DATEADD (m, 1, nd) 
  from Mth 
  where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
), Pivoted
AS
(     
    select * 
    from 
    ( 
      select MONTH(Mth.st) Month, 
          U.USER, 
          COUNT(S.QRY_ID) Searches 
      FROM Mth 
      LEFT JOIN SEARCHES S 
        on Mth.st <= S.CREATED 
        and Mth.nd > S.CREATED 
      LEFT JOIN MEMBERS U 
        on U.AID = S.AID 
      GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
    ) src 
    pivot 
    ( 
      sum(searches) 
      for month in ([12],[11],[10]) 
    ) piv
)
SELECT * 
FROM Pivoted
ORDER BY Dec

【讨论】：

@greener - 抱歉，它是 DEC，或者您想要订购的任何其他列。
这是对枢轴操作的输出进行排序的出色解决方案。据我了解，否则不可能。
一两句话来解释你在做什么以及它为什么起作用会非常有用。我想通了，但几句话会有所帮助。我必须在两段代码上“找出差异”！
添加一些评论真的很有用