如何从包含数组数组的JSON中获取数据到颤动的对象中

Question

我得到的 json 看起来像这样：

{"-N42h_BKjWaEZRJyH8vS":[{"Data":"06/2022","imie":"John","DayList":[["7.50","12.00"],["00.00","00.00"],["8.00","16.00"],["00.00","00.00"],["00.00","00.00"],["7.50","15.00"],["00.00","00.00"],["00.00","00.00"],["00.00","00.00"],["8.00","15.25"],["00.00","00.00"],["00.00","00.00"],["7.50","15.00"],["00.00","00.00"]],"surname":"Smith"}]}

“DayList”中的每个列表代表单独的工作日。例如。 ["7.50","12.00"] 只是说，工作时间从 7.30 开始，到 12 结束。每天的索引也代表一个月中的一天。索引 0 是 01/06/2022，索引 1 是 02/06/2022，依此类推。整个列表附加到一个人，在本例中为 John Smith。

我的 Day 模型如下所示：

class Day {
  String name;
  DateTime dateTime;
  double startTime;
  double endTime;

  Day({
    required this.name,
    required this.dateTime,
    required this.startTime,
    required this.endTime,
  });
}

任何人都知道如何基于这个 json 创建对象列表？ 也许有更好的方法来创建这样的 json？

Answer 1

class DayDatum {
DayDatum({
    this.data,
    this.imie,
    this.dayList,
    this.surname,
});

String data;
String imie;
List<List<String>> dayList;
String surname;

factory DayDatum.fromJson(Map<String, dynamic> json) => DayDatum(
    data: json["Data"],
    imie: json["imie"],
    dayList: List<List<String>>.from(json["DayList"].map((x) => List<String>.from(x.map((x) => x)))),
    surname: json["surname"],
);

Map<String, dynamic> toJson() => {
    "Data": data,
    "imie": imie,
    "DayList": List<dynamic>.from(dayList.map((x) => List<dynamic>.from(x.map((x) => x)))),
    "surname": surname,
};
}

您可以使用此模型来解析每个对象的数据

Answer 2

import 'dart:convert';

Data dataFromJson(String str) => Data.fromJson(json.decode(str));

String dataToJson(Data data) => json.encode(data.toJson());

class Data {
  Data({
    this.listOfDays,
  });

  List<personalInfo>? listOfDays;

  factory Data.fromJson(Map<String, dynamic> json) => Data(
        listOfDays: List<personalInfo>.from(json["-N42h_BKjWaEZRJyH8vS"]
            .map((x) => personalInfo.fromJson(x))),
      );

  Map<String, dynamic> toJson() => {
        "-N42h_BKjWaEZRJyH8vS":
            List<dynamic>.from(listOfDays!.map((x) => x.toJson())),
      };
}

class personalInfo {
  personalInfo({
    this.data,
    this.imie,
    this.dayList,
    this.surname,
  });

  String? data;
  String? imie;
  List<List<String>>? dayList;
  String? surname;

  factory personalInfo.fromJson(Map<String, dynamic> json) =>
      personalInfo(
        data: json["Data"],
        imie: json["imie"],
        dayList: List<List<String>>.from(
            json["DayList"].map((x) => List<String>.from(x.map((x) => x)))),
        surname: json["surname"],
      );

  Map<String, dynamic> toJson() => {
        "Data": data,
        "imie": imie,
        "DayList": List<dynamic>.from(
            dayList!.map((x) => List<dynamic>.from(x.map((x) => x)))),
        "surname": surname,
      };
}

您也可以使用this 网站直接创建模型

Answer 3

import 'dart:convert';
import 'package:http/http.dart' as http;

class Album {
  final List<Item> list;
  const Album({required this.list});
}

class Item {
  final int userId;
  final int id;
  final String title;
  const Item({required this.userId, required this.id, required this.title});
  factory Item.fromJson(Map<String, dynamic> json) =>
      Item(userId: json['userId'], id: json['id'], title: json['title']);
}

Future<Album> fetchAlbum() async {
  List<Item> result = [];
  final response = await http
      .get(Uri.parse('https://jsonplaceholder.typicode.com/albums?_limit=3'));
  if (response.statusCode == 200) {
    for (var element in jsonDecode(response.body)) {
      result.add(Item.fromJson(element));
    }
    return Album(list: result);
  } else {
    throw Exception('Opps, something went wrong!');
  }
}

void main(List<String> args) {
  fetchAlbum().then((value) => print(value.list[0].title));
}