如何从 Unity 的 json 中包含对象数组的对象获取信息？

Question

我有一个这样的 JSON 文件设置

{
  "cards": [
    {
      "id": "sand_bags",
      "type": "Structure",
      "name": "Sand Bags",
      "values": [
        {
          "civilian": 1,
          "fiend": -1
        }
      ],
      "effectTexts": [
        {
          "civilian": "Add +1 to your BUNKER.",
          "fiend": "Send any CIVILIAN'S +1 STRUCTURE to the SCRAPYARD."
        }
      ],
      "flavorTexts": [
        {
          "civilian": "They're just heavy bags with sand. Not much else to say, but they'll slow down an attack from a fiend. Good luck, you'll need it!",
          "fiend": "You've spotted a pretty bad STRUCTURE in this BUNKER. Time to do some damage."
        }
      ],
      "staysOnField": [
        {
          "civilian": true,
          "fiend": false
        }
      ],
      "amountInDeck": 5
    }
  ]
}

我也有一个卡片脚本

[Serializable]
public class Cards
{
    public Card[] cards;
}

[Serializable]
public class Card
{
    public string id;
    public string type;
    public string name;

    public int amountInDeck;
}

public class Values
{
    public int civilian;
    public int fiend;
}

然后我有一个 CardEffects 脚本用于我的功能。

public class CardEffects : MonoBehaviour
{
    public TextAsset jsonFile;

    public Values values;

    void Start()
    {
        Cards cardsInJson = JsonUtility.FromJson<Cards>(jsonFile.text);

        foreach (Card card in cardsInJson.cards)
        {
            Debug.Log("Card name: " + card.name + " with " + values.civilian + " in the deck.");
        }
    }
}

我已经搜索了所有内容，试图找出如何获取“值”对象的数组。我做到了这一点，无论 JSON 中“值”中的信息如何，打印的值始终为 0。如果我使类可序列化，我可以更改值并且它可以工作，但我希望这些值是它们在 JSON 中声明的任何值。有没有更好的方法来做到这一点？

请记住，我是 C# 和 Unity 的新手。我通常用 JS 编写代码，其中使用 JSON 文件对我来说没什么大不了的，我认为这是最好的方法。

Answer 1

您的 json 和您的 classes 不匹配。不仅您的json 甚至不是有效的Json。下面我给你正确的json和class。

{
  "cards": [
    {
      "id": "sand_bags",
      "type": "Structure",
      "name": "Sand Bags",
      "values": [
        {
          "civilian": 1,
          "fiend": -1
        }
      ],
      "effectTexts": [
        {
          "civilian": "Add +1 to your BUNKER.",
          "fiend": "Send any CIVILIAN'S +1 STRUCTURE to the SCRAPYARD."
        }
      ],
      "flavorTexts": [
        {
          "civilian": "They're just heavy bags with sand. Not much else to say, but they'll slow down an attack from a fiend. Good luck, you'll need it!",
          "fiend": "You've spotted a pretty bad STRUCTURE in this BUNKER. Time to do some damage."
        }
      ],
      "staysOnField": [
        {
          "civilian": true,
          "fiend": false
        }
      ],
      "amountInDeck": 5
    }
  ] // <---- This was missing
}

对于那个 Json，这就是你的 card 类的样子：

public Card 
{
    public string id { get; set; }
    public string type { get; set; }
    public string name { get; set; }
    public Values[] values { get; set; }
    public Values[] effectTexts { get; set; }
    public Values[] staysOnField { get; set; }
    public int amountInDeck { get; set; }
}

你的Values 类必须是这样的：

public class Values
{
    public object civilian;
    public object fiend;
}

Answer 2

我建议MiniJson。 您只需将脚本复制粘贴到您的项目中，就可以开始了。 然后可以调用Json.Deserialize(string json) 传递您的字符串。对于数组的情况，您可以执行以下操作：

IList myJsonElements = (IList)Json.Deserialize(string json);

找到工作的sn-p：

using System;
using Newtonsoft.Json;

namespace ConsoleApp3
{
  class Program
  {
    static void Main(string[] args) {
      string myJson = "{\"cards\": [{\"id\": \"sand_bags\",\"type\": \"Structure\",\"name\": \"Sand Bags\",\"values\": [{\"civilian\": 1,\"fiend\": -1}],\"effectTexts\": [{\"civilian\": \"Add +1 to your BUNKER.\",\"fiend\": \"Send any CIVILIAN'S +1 STRUCTURE to the SCRAPYARD.\"}],\"flavorTexts\": [{\"civilian\": \"They're just heavy bags with sand. Not much else to say, but they'll slow down an attack from a fiend. Good luck, you'll need it!\",\"fiend\":\"You've spotted a pretty bad STRUCTURE in this BUNKER. Time to do some damage.\"}],\"staysOnField\": [{\"civilian\": true,\"fiend\": false}],\"amountInDeck\": 5}]}";
      var myJsonElements = MiniJSON.Json.Deserialize(myJson);
      Console.WriteLine(myJsonElements.ToString());
      string json = JsonConvert.SerializeObject(myJsonElements, Formatting.Indented);
      Console.WriteLine(json);
      Console.ReadLine();
    }
  }
}