Python While 循环与 if 和 else 与计数特殊条件答案

【问题标题】：Python While Loop with if and else with counting on special conditionPython While 循环与 if 和 else 与计数特殊条件
【发布时间】：2022-09-23 22:42:27
【问题描述】：

最近我有一个 python While 循环函数，它带有需要特殊条件来处理的 if 功能

import time
from random import randint

while True:

    bid = randint(1,21)
    ask = 20

    #Condition 1
    if ask >= bid:
        print (\'Condition 1: ask is bigger!\')
        time.sleep (0.1)
        
    #Condition 2
    else:
        print (\'Condition 2: bid is bigger!\')

    time.sleep(0.1)

我不想让这个无限循环运行，我想添加另一个功能，如果“条件 1”在终端中连续出现 10 次，它必须打印“条件 3：条件 1 已经出现 10 次！”

有人有想法么？非常感谢！

创建一个从零开始的计数器，在条件 1 上增加它，在条件 2 上将其设置为零，条件 3 是计数器 == 10

标签： python

【解决方案1】：

这将检查 10 个连续条件 1 并跳出循环

import time
from random import randint


condition1_counter = 0
while True:

    bid = randint(1,21)
    ask = 20

    # Condition 1
    if ask >= bid:
        print ('Condition 1: ask is bigger!')
        condition1_counter += 1
        
    # Condition 2
    else:
        print ('Condition 2: bid is bigger!')
        condition1_counter = 0

    # Condition 3
    if condition1_counter == 10:
        print('Condition 3: Condition 1 occur 10 times already!')
        break

    time.sleep(0.1)

【讨论】：

【解决方案2】：

添加一个简单的计数器变量应该可以完成这项工作！

你可以初始化一个变量，比如cond1_count。在条件 1 之后增加它，在条件 2 之后减少它。

import time
from random import randint

cond1_count = 0
while True:

    bid = randint(1,21)
    ask = 20
    print(bid, ask)
    
    if cond1_count and cond1_count%10 == 0:
        print('Condition 3: Condition 1 occur 10 times already!')
        time.sleep(0.1) # or break loop if oyu want!

    #Condition 1
    if ask >= bid:
        print ('Condition 1: ask is bigger!')
        cond1_count += 1
        time.sleep (0.1)
        
    #Condition 2
    else:
        print ('Condition 2: bid is bigger!')
        cond1_count -= 1

    time.sleep(0.1)

【讨论】：

【解决方案3】：

import time
from random import randint

check = True
counter = 0
while check:

    bid = randint(1,21)
    ask = 20

    #Condition 1
    if ask >= bid:
        counter += 1
        print ('Condition 1: ask is bigger!')
        time.sleep (0.1)
    #Condition 2
    else:
        print ('Condition 2: bid is bigger!')
    #Condition 3
    if counter == 10:
        print('Condition 3: Condition 1 occur 10 times already!')
        check = False

    time.sleep(0.1)

【讨论】：

【解决方案4】：

就像是：

import time
from random import randint

condition_1_counter = 0

while True:

    bid = randint(1,21)
    ask = 20

    #Condition 1
    if ask >= bid:
        print ('Condition 1: ask is bigger!')
        time.sleep (0.1)
    
        condition_1_counter += 1
    
    if condition_1_counter >= 10:
        print("Condition 3: Condition 1 occur 10 times already!")
        
    #Condition 2
    else:
        print ('Condition 2: bid is bigger!')

    time.sleep(0.1)

然后，您可以根据需要将其重置为 0。

【讨论】：

【解决方案5】：

除了使用while 循环，您还可以使用for 循环10 次！

这是代码，然后，

for i in range(0, 10)
    bid = randint(1,21)
    ask = 20

    #Condition 1
    if ask >= bid:
        print ('Condition 1: ask is bigger!')
        time.sleep (0.1)
    
        condition_1_counter += 1
    
    if if i == 10: # it will run 10 times!
        print("Condition 3: Condition 1 occur 10 times already!")
        
    #Condition 2
    else:
        print ('Condition 2: bid is bigger!')

    time.sleep(0.1)

这应该可以正常工作！

【讨论】：

他想停在 10连续的条件 1...无论结果如何，这只会运行 10 次