将numpy列表数组转换为int数组[重复]

Question

我有一个由单个元素列表组成的二维 numpy 数组：

aaa = np.array(
[[ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ],
 [ [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0] ],
 [ [0], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4], [4] ] ]
)

如何将内部列表转换为 int，这样我就有：

nnnn = np.array(
    [[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ],
     [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ],
     [0, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4 ]]
)

听起来很简单，但我尝试过的任何事情最终都会得到一个列表 或者我尝试将sum() 作为一种对列表中的值求和的技术，但最终只求和。

Answer 1

你可以这样做：

nnnn = np.array([l.flatten() for l in aaa])

你也可以使用reshape:

nnnn = aaa.reshape(-1, aaa.shape[1])

甚至更简单：

nnnn = aaa[:,:,0]