【发布时间】:2019-08-05 05:03:26
【问题描述】:
我为一个用 python 编写的井字游戏编写了代码。我完全按照这些步骤操作,但我认为该游戏是专门为 Jupyter 笔记本编写的,因为它在真正的 Python 解释器中无法正常工作(我在 VS 代码中写出了所有代码)。它随机分配哪个玩家先走,哪个玩家应该先走,但该玩家的标记没有正确分配,另一个玩家永远无法移动。此外,移动的玩家,无论何时选择顶行的位置(索引 7-9),都将自动获胜。
这是在 Python 3 中。我尝试过调试,但代码在语法上是有效的,所以我无法查明它的逻辑问题。
def display_board(board): # Board setup
print('\n'*100)
print(board[7] + '|' + board[8] + '|' + board[9])
print(board[4] + '|' + board[5] + '|' + board[6])
print(board[1] + '|' + board[2] + '|' + board[3])
def player_input(): # Player assignment - use while loop to keep asking until a valid character is entered
marker = ''
while marker != 'X' and marker != 'O':
marker = input('Player1: Choose X or O: ').upper()
if marker == 'X':
return ('X','O')
else:
return ('O','X')
def place_marker(board, marker, position): # Allows player to place their marker at specific board index
board[position] = marker
def win_check(board, mark): # Check all rows, columns, diagonals for sharing the same marker to check for a winner
return ((board[1] and board[2] and board[3] == mark) or # Rows
(board[4] and board[5] and board[6] == mark) or
(board[7] and board[8] and board[9] == mark) or
(board[1] and board[4] and board[7] == mark) or # Columns
(board[2] and board[5] and board[8] == mark) or
(board[3] and board[6] and board[9] == mark) or
(board[1] and board[5] and board[9] == mark) or # Diagonals
(board[3] and board[5] and board[7] == mark))
import random
def choose_first(): # Randomize who goes first
flip = random.randint(0,1)
if flip == 0:
return 'Player 1'
else:
return 'Player 2'
def space_check(board, position): # Check to see if a space on the board is still available
return board[position] == ' '
def full_board_check(board): # Checks to see if board is full resulting in a draw
for i in range(1,10):
if space_check(board,i): # If there is free space, board is NOT full
return False
return True
def player_choice(board): # Asks for the player's next move choice
position = 0
while position not in [1,2,3,4,5,6,7,8,9] or not space_check(board, position):
position = int(input('Choose a position: (1-9): '))
return position
def replay(): # Asks if the players want to play again
choice = input("Play again? Enter Yes or No: ")
return choice == 'Yes'
# Logic to run the game
# While loop needed to keep running the game
# Need to break out of the while loop on replay()
print ('Welcome to TIC TAC TOE')
while True:
# Game Setup (Board, Players, Player turns)
the_board = [' ']*10
player1_marker,player2_marker = player_input()
turn = choose_first()
print(turn + ' will go first')
play_game = input('Ready to play? y or n: ')
if play_game == 'y':
game_on = True
else: game_on = False
# Game Play
while game_on:
if turn == 'Player1':
# Show the board
display_board(the_board)
# Choose a place to move
position = player_choice(the_board)
# Place the marker on the position
place_marker(the_board,player1_marker,position)
# Check if they won
if win_check(the_board,player1_marker):
display_board(the_board)
print('PLAYER 1 HAS WON!')
game_on = False
else:
if full_board_check(the_board): # Check for tie
display_board(the_board)
print("TIE GAME!")
game_on = False
else:
turn = 'Player 2'
else:
# Show the board
display_board(the_board)
# Choose a place to move
position = player_choice(the_board)
# Place the marker on the position
place_marker(the_board,player2_marker,position)
# Check if they won
if win_check(the_board,player2_marker):
display_board(the_board)
print('PLAYER 2 HAS WON!')
game_on = False
else:
if full_board_check(the_board):
display_board(the_board)
print("TIE GAME!")
game_on = False
else:
turn = 'Player 1'
if not replay():
break
我希望游戏在每个玩家之间来回切换,并分配给他们正确的标记,但我无法弄清楚为什么没有发生这种情况,因为它看起来对我来说是正确的。
【问题讨论】:
-
你的代码太复杂了。尝试使用简单的二维矩阵作为电路板。我敢肯定,一旦您将事情简化一点,您就会发现问题,对于没有编写代码的人来说,这将更加困难。
标签: python tic-tac-toe