如何将连接查询的两行输出合并为一行？ [复制]

Question

我有两张表 Slot 和 Timetable
插槽：

slotID|startTime|endTime
------------------------
1     |10:00:00|12:00:00
2     |13:00:00|15:00:00

时间表：

ScheduleID|slotID|subjectID|day
-------------------------------
1         |1     |subject1 |mon
2         |2     |subject1 |mon
3         |1     |subject2 |tue
4         |2     |subject2 |tue

我试过了

    SELECT slot.startTime, slot.endTime,
    (CASE WHEN day="mon" THEN timetable.subjectID END) as Monday,
    (CASE WHEN day="tue" THEN timetable.subjectID END) as Tuesday
    FROM timetable
    INNER JOIN slot ON timetable.slotID=slot.slotID

我得到了：

startTime|endTime|Monday  |Tuesday
---------------------------------------
10:00:00|12:00:00|subject1|NULL
10:00:00|12:00:00|NULL    |subject2
13:00:00|15:00:00|subject1|NULL
13:00:00|15:00:00|NULL    |subject2

我想编写一个 SQL 查询来输出 8 列以打印如下所示的内容

startTime |endTime |   mon  |   tue  |   wed  |   thu  |   fri  |   sat  
-------------------------------------------------------------------------
 10:00:00 |12:00:00|subject1|subject2|subject1|subject2|subject1|subject2
 13:00:00 |15:00:00|subject1|subject2|subject1|subject2|subject1|subject2

我想删除 NULL 值并合并具有相同 startTime 和 endTime 的行。任何帮助将不胜感激

Answer 1

你想要聚合：

SELECT s.startTime, s.endTime,
       MAX(CASE WHEN day = 'mon' THEN tt.subjectID END) as Monday,
       MAX(CASE WHEN day = 'tue' THEN tt.subjectID END) as Tuesday
FROM timetable tt INNER JOIN
     slot s
     ON tt.slotID = s.slotID
GROUP BY s.startTime, s.endTime;