如何将两个连接查询合并为一个？

Question

我有点迷路了，我需要加入两个连接查询来形成一个表。这是我正在编写的脚本...

SELECT Email, Domain, site.SiteID, site.SiteName, Status, LastLogin, up.UPID, up.UPName, trd.TRMCID, trd.TRMCName
FROM UserDetails as ud
INNER JOIN SiteLocation as site
on ud.SiteID = site.SiteID

INNER JOIN UltimateParent as up
on ud.UPID = up.UPID

INNER JOIN TRMCDetails as trd
on ud.TRMCID = trd.TRMCID

SELECT SiteID, cinfo.CountryCode, Country
From Country as cntry
INNER JOIN CountryInfo as cinfo
on cntry.CountryCode = cinfo.CountryCode

INNER JOIN SiteLocation as site2
on cntry.CountryCode = site2.CountryCode

我需要显示国家，但国家代码与 SiteID 相关联。我很难加入他们两个。

这是第一个表的样子

Email-Domain-SiteID-SiteName-Status-LLogin-UPID-UPName-TRMCID-TRMCName

这是第二张桌子的样子

SiteID-CountryCode-Country

我需要第三张桌子看起来像这样

Email-Domain-SiteID-SiteName-Status-LLogin-UPID-UPName-TRMCID-TRMCName-Country

但是，我在合并之前创建的两个联接时遇到了问题。

提前感谢您的帮助！

干杯！

Answer 1

试试喜欢：

SELECT
    Email,
    Domain,
    site.SiteID,
    site.SiteName,
    Status,
    LastLogin,
    up.UPID,
    up.UPName,
    trd.TRMCID,
    trd.TRMCName,
    cinfo.CountryCode,
    cntry.Country
FROM UserDetails as ud
    INNER JOIN UltimateParent up on ud.UPID = up.UPID
    INNER JOIN TRMCDetails trd on ud.TRMCID = trd.TRMCID
    INNER JOIN CountryInfo cinfo on cntry.CountryCode = cinfo.CountryCode
    INNER JOIN SiteLocation site on ud.SiteID = site.SiteID
    INNER JOIN Country cntry on cntry.CountryCode = site.CountryCode

Answer 2

您可以将第二个查询用作子查询。希望我能很好地理解您在寻找什么。

SELECT Email, Domain, site.SiteID, site.SiteName, Status, LastLogin, up.UPID, up.UPName, trd.TRMCID, trd.TRMCName, s1.Country
FROM UserDetails as ud
INNER JOIN SiteLocation as site
on ud.SiteID = site.SiteID
INNER JOIN UltimateParent as up
on ud.UPID = up.UPID
INNER JOIN TRMCDetails as trd
on ud.TRMCID = trd.TRMCID
INNER JOIN 
 (
  SELECT SiteID, cinfo.CountryCode, Country
  From Country as cntry
  INNER JOIN CountryInfo as cinfo
  on cntry.CountryCode = cinfo.CountryCode

  INNER JOIN SiteLocation as site2
  on cntry.CountryCode = site2.CountryCode
) s1 on s1.SiteID = site.SiteID