【发布时间】:2015-04-22 21:10:40
【问题描述】:
我在使用后台工作程序时尝试迭代一个数组,我确信这只是我的语法不正确,但我不断收到错误。有人可以帮我解决这个问题吗?
namespace Form1
{
public partial class Form1 : Form
{
public BackgroundWorker backgroundWorker1 = new BackgroundWorker();
public OpenFileDialog fd = new OpenFileDialog();
public Form1()
{
InitializeComponent();
backgroundWorker1.WorkerReportsProgress = true;
backgroundWorker1.WorkerSupportsCancellation = true;
backgroundWorker1.DoWork += new DoWorkEventHandler(backgroundWorker1_DoWork);
backgroundWorker1.ProgressChanged += new ProgressChangedEventHandler(backgroundWorker1_ProgressChanged);
}
private void btn_Two_Click(object sender, EventArgs e)
{
fd.Title = "Select The Text File To Open";
fd.Filter = "Text Files|*.txt";
fd.InitialDirectory = @"C:\";
if (fd.ShowDialog() == DialogResult.OK)
{
TextFiles(sender);
}
}
private void TextFiles(object sender)
{
IEnumerable<String> employeeNames = File.ReadLines(fd.FileName);
foreach (string pgs in employeeNames)
{
employee = pgs;
ProcessTables(employee, sender);
}
}
private void ProcessTables(string employee, object sender)
{
sw.Restart();
timer.Start();
//This line is where the compiler throws the error
backgroundWorker1.RunWorkerAsync();
}
private void backgroundworker1_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
progressBar1.Value = e.ProgressPercentage;
}
private void backgroundworker1_DoWork(object sender, DoWorkEventArgs e)
{
//Never hits this block so I will omit this code for time sake
}
}
}
【问题讨论】:
-
你的后台工作事件方法在哪里?
-
@Lloyd -- 查看编辑。我的代码实际上并没有达到这些方法,它命中了 RunWorkerAsync() 并抛出了错误
-
您在 foreach 循环中多次调用同一个后台工作程序。您可以创建多个后台工作人员(这将是一团糟)或使用多线程,如果您想同时处理文件,这将是解决此问题的正确方法。
-
查看这篇文章,了解如何为每个循环编写一个简单的并行:msdn.microsoft.com/en-us/library/dd460720%28v=vs.110%29.aspx
标签: c# backgroundworker