【发布时间】：2021-08-17 08:35:40
【问题描述】：
我有以下 python 代码，但我真的很难让它工作。
这是一个终端中的基本扫雷游戏。这个版本与其他版本有点不同，它应该首先询问用户网格有多大，然后要插入多少地雷。剩下的就是你的好老基本扫雷了。
def display():
for x in range(SIZE):
if x == 0:
print(" ", end="")
for i in range(SIZE):
print(" " + str(i), end="")
print("\n |-" + "--|-" * (SIZE - 1) + "--|")
print("0 |", end="")
for y in range(SIZE):
print(" " + str(BOARD[x][y].status) + "|", end="")
print("\n |-" + "--|-" * (SIZE -1) + "--|")
elif x == SIZE -1:
print(str(SIZE-1) + " |", end="")
for y in range(SIZE):
print(" " + str(BOARD[x][y].status) + "|", end="")
print("\n |-" + "--|-" * (SIZE -1) + "--|")
else:
print(str(x) + " |", end="")
for y in range(SIZE):
print(" " + str(BOARD[x][y].status) + "|", end="")
print("\n |-" + "--|-" * (SIZE-1) + "--|")
class Square:
def __init__(self, x, y):
self.status = "- "
self.row = x
self.column = y
self.mine = False
self.neighbours = []
self.danger = 0
def status_get(self):
return this.status
def first_move():
# establish mine locations, ignoring stating dig
print("""Where would you like to start?\n""")
while True:
a, b = input("Enter an x and y coodinate, comma separated, to dig the first square: ").split(",")
x = int(a)
y = int(b)
if x >= SIZE or y >= SIZE:
print("Out of bounds, try again.")
continue
else:
for m in range(MINES):
place_mines(x, y)
welfare(BOARD[x][y])
break
def place_mines(x, y):
# Recursively place mines, ignoring starting square
global BOARD
h = random.randint(0, SIZE - 1)
w = random.randint(0, SIZE - 1)
if h == x and w == y:
place_mines(x, y)
else:
if not BOARD[h][w].mine:
BOARD[h][w].mine = True
for sqr in BOARD[h][w].neighbours:
sqr.danger += 1
else:
place_mines(x, y)
def next_turn():
# keeps promting to dig, flag, or end the game
move = input("What would you like to do? ").lower()
if move == "!quit":
print("Thank you, come again.")
quit(0)
elif move == "d":
dig()
display()
elif move == "f":
flag()
display()
elif move == "r":
unflag()
display()
elif move == "!help":
print("!quit = Quit game.")
print("d = Uncover a square.")
print("f = Plant a flag marking a square as containing a mine.")
print("r = Remove a flag.")
else:
print("You'll have to speak up... Try again.")
def unflag():
# Unflags a previously flagged square
while True:
a, b = input("Supply an x and y coordinate to unflag: ").split(",")
x = int(a)
y = int(b)
if x >= SIZE or y >= SIZE:
print("Out of bounds, try again.")
continue
else:
global BOARD
if BOARD[x][y].status == "F ":
BOARD[x][y].status = "- "
break
def flag():
# flag a square to indicate a mine
while True:
a, b = input("Supply an x and y coordinate to flag: ").split(",")
x = int(a)
y = int(b)
if x >= SIZE or y >= SIZE:
print("Out of bounds, try again.")
continue
else:
global BOARD
BOARD[x][y].status = "F "
global FLAGS
if BOARD[x][y].mine and BOARD[x][y].status == "F ":
FLAGS += 1
break
def dig():
# Uncover a square. If it's a bomb it's game over. Otherwise, reveal nearby squares
while True:
a, b = input("Supply an x and y coordinate to dig: ").split(",")
x = int(a)
y = int(b)
if x >= SIZE or y >= SIZE:
print("Out of bounds, try again.")
continue
else:
if BOARD[x][y].mine is True:
print("BANG! You have died!")
for x in range(SIZE):
for y in range(SIZE):
sqr = BOARD[x][y]
if sqr.mine:
sqr.status = "@"
display()
quit(0)
else:
BOARD[x][y].status = "x"
welfare(BOARD[x][y])
break
def welfare(sqr, history=[]):
# update square state after each dig to reveal mine status
if sqr.danger == 0:
sqr.status = "x "
for box in sqr.neighbours:
if box not in history:
history.append(box)
welfare(box, history)
else:
if not sqr.mine:
sqr.status = str(sqr.danger) + " "
#for box in sqr.neighbours:
# if not box.mine:
# if box not in history:
# history.append(box)
# welfare(box, history)
def win_state():
# is it over, can I go home now?
global FLAGS
global MINES
global BOARD
correct = 0
if FLAGS == MINES:
for x in range(SIZE):
for y in range(SIZE):
sqr = BOARD[x][y]
if sqr.mine and sqr.status == "F ":
correct += 1
if correct == MINES:
print("Congratulations!\n")
print("You found " + str(MINES) + " mines and didn't die.")
exit(0)
def startup():
# set game parameters, give all the squares their neighbours
print("It's Minesweeper, how wide do you want the board?")
global SIZE
while True:
SIZE = int(input("Give me a size, between 3 and 10 inclusive "))
if SIZE not in range(3, 11):
print("Did I stutter? Try again. ")
continue
else:
global MINES
while True:
MINES = int(input("How many mines do you want? "))
if MINES >= SIZE ** 2:
print("Whoa! That's too many. Try Again. ")
continue
else:
break
print("OKAY")
# initialise an empty board
global BOARD
BOARD = [[None for _ in range(SIZE)] for _ in range(SIZE)]
# fill that board with square objects
for s in range(SIZE):
for d in range(SIZE):
BOARD[s][d] = Square(s, d)
# link each square to it's neighbour
for a in range(SIZE):
for b in range(SIZE):
sqr = BOARD[a][b]
if a == 0:
sqr.neighbours.append(BOARD[a + 1][b])
if b != SIZE - 1:
sqr.neighbours.append(BOARD[a + 1][b + 1])
sqr.neighbours.append(BOARD[a][b + 1])
if b != 0:
sqr.neighbours.append(BOARD[a][b - 1])
sqr.neighbours.append(BOARD[a + 1][b - 1])
elif a == SIZE - 1:
sqr.neighbours.append(BOARD[a - 1][b])
if b != SIZE - 1:
sqr.neighbours.append(BOARD[a][b + 1])
sqr.neighbours.append(BOARD[a - 1][b + 1])
if b != 0:
sqr.neighbours.append(BOARD[a - 1][b - 1])
sqr.neighbours.append(BOARD[a][b - 1])
else:
sqr.neighbours.append(BOARD[a + 1][b])
sqr.neighbours.append(BOARD[a - 1][b])
if b != SIZE - 1:
sqr.neighbours.append(BOARD[a - 1][b + 1])
sqr.neighbours.append(BOARD[a][b + 1])
sqr.neighbours.append(BOARD[a + 1][b + 1])
if b != 0:
sqr.neighbours.append(BOARD[a - 1][b - 1])
sqr.neighbours.append(BOARD[a][b - 1])
sqr.neighbours.append(BOARD[a + 1][b - 1])
startup()
while True:
next_turn()
win_state()
【问题讨论】：
-
到底是什么问题？
-
它循环初始化并且从未真正开始游戏。所以它会询问棋盘的大小，然后是地雷的数量，然后它会循环回到再次询问棋盘的大小。
-
没有什么可以阻止
startup函数中的第一个while True:循环。 -
你不需要
global X，除非你有一个声明X = something。您可以使用全局变量，甚至可以修改全局变量，只是无法替换它们。
标签： python python-3.x