如何在 PHP 中让值相互跟随？

Question

如何在一个数组中找到与另一个数组按顺序匹配的值？

这是我的代码，它为我提供了与预期结果不对应的 $Array4（如下所示）：

<?php
for ($j=0; $j < 1; $j++) {
    for ($i=0; $i < 100; $i++) {
        $Array3 = (array_intersect($Array2, $Array1));
        $Array4 = array_unique($Array3);
    }

print_r($Array4);
}
?>

$Array1：

[not] => G
[have] => L

$Array2 - 与 $Array1 匹配的数组：

[Once] => B
[uppon] => A
[a] => G
[time] => M
[,] => Z
[a] => V
[small] => G
[squirrel] => F
[,] => Z
[whitch] => U
[once] => L
[in] => N
[the] => N
[forest] => X
[,] => Z
[set] => G      \\Search 
[out] => L      \\string
[to] => V
[find] => M
[something] => N
[to] => W
[eat] => X
[,] => Z
[to] => G
[survive] => G
[.] => Z

我的代码的结果：

$Array3 - 重复：

[a] => G
[small] => G
[once] => L
[set] => G     \\Search 
[out] => L     \\string
[to] => G

$Array4 - 结果（问题是“a”和“once”在数组 $Array2 中不相互跟随）：

[a] => G
[once] => L

预期结果：

[set] => G    \\Search 
[out] => L    \\string 

Answer 1

这有望满足您的需求。

function findSameInPosition($needle, $haystack) {
    $indexedNeedle = array_values($needle);
    $indexedHaystack = array_values($haystack);
    foreach (array_keys($indexedHaystack) as $key) {
        if (array_slice($indexedHaystack, $key, count($indexedNeedle)) === $indexedNeedle) {
            return array_slice($haystack, $key, count($indexedNeedle));
        }
    }
}

// Example:

$input1 = array(
    "not" => "G",
    "have" => "L"
);

$input2 = array(
    "Once" => "B",
    "uppon" => "A",
    "a" => "G",
    "time" => "M",
    "," => "Z",
    "a" => "V",
    "small" => "G",
    "squirrel" => "F",
    "," => "Z",
    "whitch" => "U",
    "once" => "L",
    "in" => "N",
    "the" => "N",
    "forest" => "X",
    "," => "Z",
    "set" => "G",
    "out" => "L",
    "to" => "V",
    "find" => "M",
    "something" => "N",
    "to" => "W",
    "eat" => "X",
    "," => "Z",
    "to" => "G",
    "survive" => "G",
    "." => "Z"
);

findSameInPosition($input1, $input2); // Returns Array ( [set] => G [out] => L )