使用 python 列表的硬币条纹概率

Question

我试图编写一个程序来找出在随机生成的正面和反面列表中出现六个正面或六个反面的频率，但我的结果很荒谬（我得到了 150% 而其他人大约 80%）。我试图将我的程序与其他程序进行比较，但始终不明白我哪里出错了。你能告诉我有什么问题吗？

import random
TotalStreaks = 0
for experimentNumber in range(10000):
    # Code that creates a list of 100 'heads' or 'tails' values.
    explist = []
    numberOfStreaks = 0
    for value in range(100):
        if random.randint(0,1) == 0:
            explist.append('H')
        else:
            explist.append('T')

    # Code that checks if there is a streak of 6 heads or tails in a row.
    for i in range(95): #we are comparing the value of the next 5 values so we want the range to be 100-5

        #compare the element i with the next five elements to see if they match

        if explist[i] == explist[i+1] == explist[i+2] == explist[i+3] == explist[i+4] == explist[i+5]:

            #see if it's the first streak (a.k.a. numberOfStreaks == 0) or
            #if i is not equal to the 5 indexes that follow the most recent index of a streak 

            if numberOfStreaks == 0 or i not in rep:
                numberOfStreaks+=1

                #rep is the list of the indexes of the 5 numbers following the number i
                #which is where the streak was identified

                rep = [i+1, i+2, i+3, i+4, i+5]
                
    TotalStreaks += numberOfStreaks
                
print('Chance of streak: %s%%' % ((TotalStreaks / 10000) * 100))

Answer 1

我认为问题出在最后一条语句

如果您将最后一条语句更改为以下语句：

print('Chance of streak: {:.2f}%'.format((TotalStreaks / 10000) * 100))

我还对代码做了一些小改动，没有改变逻辑。

import random

rep = []
TotalStreaks = 0
for experimentNumber in range(10000):
    # Code that creates a list of 100 'heads' or 'tails' values.
    explist = []
    numberOfStreaks = 0
    for value in range(100):
        if random.randint(0, 1) == 0:
            explist.append('H')
        else:
            explist.append('T')

    # Code that checks if there is a streak of 6 heads or tails in a row.
    for i in range(95):  # we are comparing the value of the next 5 values so we want the range to be 100-5

        # compare the element i with the next five elements to see if they match

        if explist[i] == explist[i + 1] == explist[i + 2] == explist[i + 3] == explist[i + 4] == explist[i + 5]:

            # see if it's the first streak (a.k.a. numberOfStreaks == 0) or
            # if i is not equal to the 5 indexes that follow the most recent index of a streak

            if numberOfStreaks == 0 or i not in rep:
                numberOfStreaks += 1

                # rep is the list of the indexes of the 5 numbers following the number i
                # which is where the streak was identified
                
                rep.append(i + 1)
                rep.append(i + 2)
                rep.append(i + 3)
                rep.append(i + 4)
                rep.append(i + 5)

    TotalStreaks += numberOfStreaks

print('Chance of streak: {:.2f}%'.format((TotalStreaks / 10000) * 100))

这是输出：

Chance of streak: 80.61%