python3下实现url检测并发送告警邮件

创建存放url的文档info_url，检测url并将返回值和url写入新文件info_sta


import requests

def url():
    with open(\'info_url\') as f:
        with open(\'info_sta\',\'w\') as f1:
            st = \'\'
            for line in f:
                line = line.strip()
                sta = str(requests.get(line).status_code)
                st = line+\'|\'+sta
                f1.write(st+\'\n\')

    with open(\'info_sta\') as f:
        st = \'\'
        for line in f:
            url,status = line.strip().split(\'|\')
            if status != \'404\':
                st = st + url + \'\n\'
    return st

主程序


import sys
import os
from email.mime.text import MIMEText
import smtplib
from email.header import Header
sys.path.insert(0,os.path.dirname(os.getcwd()))
import check_status

url = check_status.url()

mail_host = \'smtp.ym.163.com\'  #smtp
mail_user = \'baojing@zenking.cc\'
mail_pass = \'chanjing\'

receivers = [\'wzxing21@sina.com\',\'1506353195@qq.com\']

#第一部分是文本内容，第二部分plain设置文本格式，第三部分是编码设置
message = MIMEText(\'URL检测失败 :\n%s\'%url,\'plain\',\'utf-8\')
message[\'From\'] = mail_user
message[\'To\'] = Header(\'wzxing21@sina.com,1506353195@qq.com\')

subject = \'邮件告警\'    #主题
message[\'subject\'] = Header(subject,\'utf-8\')

smtpobj = smtplib.SMTP(\'smtp.ym.163.com\')
smtpobj.login(mail_user,mail_pass)
smtpobj.sendmail(mail_user,receivers,message.as_string())
print(\'发送成功\')