python读取excel，数字都是浮点型，日期格式是数字的解决办法

excel文件内容：

 

读取excel：

# coding=utf-8
import xlrd
import sys

reload(sys)
sys.setdefaultencoding(\'utf-8\')
import traceback


class excelHandle:
    def decode(self, filename, sheetname):
        try:
            filename = filename.decode(\'utf-8\')
            sheetname = sheetname.decode(\'utf-8\')
        except Exception:
            print traceback.print_exc()
        return filename, sheetname

    def read_excel(self, filename, sheetname):
        filename, sheetname = self.decode(filename, sheetname)
        rbook = xlrd.open_workbook(filename)
        sheet = rbook.sheet_by_name(sheetname)
        rows = sheet.nrows
        cols = sheet.ncols
        all_content = []
        for i in range(rows):
            row_content = []
            for j in range(cols):
                cell = sheet.cell_value(i, j)
                row_content.append(cell)
            all_content.append(row_content)
            print \'[\' + \',\'.join("\'" + str(element) + "\'" for element in row_content) + \']\'
        return all_content


if __name__ == \'__main__\':
    eh = excelHandle()
    filename = r\'G:\test\ctype.xls\'
    sheetname = \'Sheet1\'
    eh.read_excel(filename, sheetname)

输出：

[\'整形\',\'175.0\']
[\'字符串\',\'最后的骑士\']
[\'浮点型\',\'6.23\']
[\'日期\',\'42909.6461574\']
[\'空值\',\'\']
[\'布尔型\',\'1\']

可以看到，数字一律按浮点型输出，日期却输出成一串小数？！布尔型输出0或1

 

代码稍做改动：来看一看表格的数据类型

        for i in range(rows):
            row_content = []
            for j in range(cols):
                ctype = sheet.cell(i, j).ctype #表格的数据类型
                print ctype,
                cell = sheet.cell_value(i, j)
                row_content.append(cell)
            all_content.append(row_content)
            print
            print \'[\' + \',\'.join("\'" + str(element) + "\'" for element in row_content) + \']\'

输出：

1 2
[\'整形\',\'175.0\']
1 1
[\'字符串\',\'最后的骑士\']
1 2
[\'浮点型\',\'6.23\']
1 3
[\'日期\',\'42909.6461574\']
1 0
[\'空值\',\'\']
1 4
[\'布尔型\',\'1\']

python读取excel中单元格的内容返回的有5种类型，即上面例子中的ctype:

ctype： 0 empty,1 string, 2 number, 3 date, 4 boolean, 5 error

 

所以，判断一下ctype，然后再做相应处理就可以了。

 

最终代码：

# coding=utf-8
import xlrd
import sys

reload(sys)
sys.setdefaultencoding(\'utf-8\')
import traceback
from datetime import datetime
from xlrd import xldate_as_tuple


class excelHandle:
    def decode(self, filename, sheetname):
        try:
            filename = filename.decode(\'utf-8\')
            sheetname = sheetname.decode(\'utf-8\')
        except Exception:
            print traceback.print_exc()
        return filename, sheetname

    def read_excel(self, filename, sheetname):
        filename, sheetname = self.decode(filename, sheetname)
        rbook = xlrd.open_workbook(filename)
        sheet = rbook.sheet_by_name(sheetname)
        rows = sheet.nrows
        cols = sheet.ncols
        all_content = []
        for i in range(rows):
            row_content = []
            for j in range(cols):
                ctype = sheet.cell(i, j).ctype  # 表格的数据类型
                cell = sheet.cell_value(i, j)
                if ctype == 2 and cell % 1 == 0:  # 如果是整形
                    cell = int(cell)
                elif ctype == 3:
                    # 转成datetime对象
                    date = datetime(*xldate_as_tuple(cell, 0))
                    cell = date.strftime(\'%Y/%d/%m %H:%M:%S\')
                elif ctype == 4:
                    cell = True if cell == 1 else False
                row_content.append(cell)
            all_content.append(row_content)
            print \'[\' + \',\'.join("\'" + str(element) + "\'" for element in row_content) + \']\'
        return all_content


if __name__ == \'__main__\':
    eh = excelHandle()
    filename = r\'G:\test\ctype.xls\'
    sheetname = \'Sheet1\'
    eh.read_excel(filename, sheetname)

输出：

[\'整形\',\'175\']
[\'字符串\',\'最后的骑士\']
[\'浮点型\',\'6.23\']
[\'日期\',\'2017/23/06 15:30:28\']
[\'空值\',\'\']
[\'布尔型\',\'True\']

 

更多操作excel可参考：http://www.2cto.com/kf/201501/373655.html